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the function can only take one input argument

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Nawaf Aldhawi
Nawaf Aldhawi el 8 de Jun. de 2022
Editada: Jan el 8 de Jun. de 2022
so when i a make a function called analyzeT to analyze temperatures i can't enter the temp's this way "analyzeT(28,44,50,33)' it tells me that there's too many input arguments but when i make a vector first and store the values in it then i write 'analyzeT(vector)' it works, anyway i can make the first way work? thanks!
this is the function
function [maxT,minT,avgT] = analyzeT(temp)
i = length(temp);
maxT = temp(2);
minT = temp(1);
sum = 0;
for i = 1:i
if temp(i) > maxT
maxT = temp(i);
elseif temp(i) < temp(1)
minT = temp(i);
else
end
sum = temp(i) + sum;
end
avgT = sum/length(temp);
end
  1 comentario
Jan
Jan el 8 de Jun. de 2022
Editada: Jan el 8 de Jun. de 2022
Why do you assume, that maxT cannot be temp(1) ?
This is not a but, but very ugly:
i = length(temp);
for i = 1:i
If maxT and minT are set to temp(1), you do not have to check temp(1) again.
Together:
nTemp = length(temp);
maxT = temp(1);
minT = temp(1);
sumTemp = temp(1);
for i = 2:nTemp
...
end
Avoid using the names of builtin functions as variables. This is not an error, but a frequent source of unexpected behavior if you use the function sum() later.
I do not think, that this is exactly what you want:
elseif temp(i) < temp(1)
minT = temp(i);
else % Omit this orphaned else, if it is not used.
end
Do you really want to compare the temperatures with temp(1), or with minT?

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Jan
Jan el 8 de Jun. de 2022
Editada: Jan el 8 de Jun. de 2022
Either modify the call to create the vector dynamically:
analyzeT([28,44,50,33])
% ^ ^
Or create a new input interface for the function (which is not efficient or nice in this example):
function [maxT,minT,avgT] = analyzeT(varargin)
if nargin == 1
temp = varargin{1};
else
remp = [varargin{:}]; % Concatenate inputs to a vector
end
...

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