How can I find all n-bit semiprime numbers?

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Nadatimuj
Nadatimuj el 25 de Jun. de 2022
Editada: John D'Errico el 25 de Jun. de 2022
I know about the primes function but I need to get a list of all n-bit semiprime numbers and all the factors. Thanks.
  9 comentarios
Torsten
Torsten el 25 de Jun. de 2022
Editada: Torsten el 25 de Jun. de 2022
The problem is in giving up, with no effort shown or made.
Yes, that's the decisive distinction. But here, the usual terminology is "This smells like homework" where it should read "This smells like laziness".
Nadatimuj
Nadatimuj el 25 de Jun. de 2022
@John D'Errico Thanks for the code, it is perfect!
When I mean research I mean is: I am responsible to develop the Ising machine I am trying to build that will factorize many numbers. Generating semiprime number is nothing novel or not treated as a research topic in my case. Yes, in many cases problem generation is also an important reseach topic, but if it is not something new, it's not even something publishable. Thank you both.

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John D'Errico
John D'Errico el 25 de Jun. de 2022
Editada: John D'Errico el 25 de Jun. de 2022
Ok, I'll give in. A reasonable question, with a reason to be asked. Given a valid reason for the question, I am actuually quite happy to help. :)
The underlying problem is that of factoring large numbers. When is that difficult? When you have a number with explicitly two large prime factors. In fact, the worst such problems are probably where both factor are as close as possible to each other. Effectively, a nasty problem is one where both factors are very near sqrt(N).
The simplest scheme I would use here is based on nextprime. I wrote a version that lives in my variable precision integer codes, but there is also one in the symbolic toolbox. Unfortunately, the sym version has a limited capability in some respects. Oh well. I'll use it anyway, rather than asking you to use my own toolbox. (This will be an incentive though for me to prompt the symbolic TB team to improve their version of nextprime.)
For example, suppose I wanted to find a large semi-prime, with two factors very close to each other? I'll pick N = 50, where I want to find a semi-prime near 2^(2*N). This will be a seriously large number, and finding semi-primes near that number COULD take some effort.
m = 5; % find m semi-primes nead 2^100, all of which will suffer nasty factoring problems.
N = 50;
% First, find the first 10 primes larger than 2^N.
P_hi = zeros(m,1,'sym');
p = sym(2)^N;
for i = 1:m
p = nextprime(p+1);
P_hi(i) = p;
end
So we have now found 5 large primes, all of which exceed 2^50 by just a small amount. Next, we need to find 10 large primes, all of hich are just a weee bit less than 2^50. ARGH. I really want sym/nextprime to have been written better. So I need to do that myself? Maybe. I wanted sym/nextprime to generate the list I have above. As well, I want the ability to fine the next primes that are just LESS than the target. Hmm. I think I have a project to write soon. But even so, we can do this:
P_lo = zeros(m,1,'sym');
p = floor(sym(2)^N*0.99);
for i = 1:m
p = nextprime(p+1);
P_lo(i) = p;
end
Plist = P_lo.*P_hi;
[P_lo,P_hi,Plist]
ans = 
So very efficiently generated, here are 5 distinct semi-primes, all of which are roughly 2^100. Just a bit less in fact. The two prime factors are within 1% of each other by design, so they will form arguably difficult to factor numbers. A larger such list of semi-primes would be trivially generated, just make m larger. You can make the pair of primes closer together if you wish, by making that factor of 0.99 closer to 1.
tic
factor(Plist(1))
ans = 
toc
Elapsed time is 0.513973 seconds.
tic
factor(Plist(1) + 2)
ans = 
toc
Elapsed time is 0.070427 seconds.
As you will expect factoring these particularly rough numbers is more difficult, taking more time than factoring some random integer in that general vicinity.

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