passing a function to another function

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R yan
R yan el 3 de Feb. de 2015
Comentada: R yan el 3 de Feb. de 2015
Hi
I am trying to pass the following function "haar" to the function integral. I am getting the following error. plz suggest. thanks
function val = haar(x)
if ((0<=x) && (x<0.5))
val=1;
elseif ((0.5<= x) && (x < 1))
val =-1;
else
val =0;
end
end
EDU>> fhnadle=@haar;
EDU>> integral(fhnadle,0,1)
Operands to the || and && operators must be convertible to logical scalar values

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Sean de Wolski
Sean de Wolski el 3 de Feb. de 2015
Editada: Sean de Wolski el 3 de Feb. de 2015
integral calls the function with a vector x, you're expecting x to be a scalar in your haar function. E.g:
>> [1 2 3] && 1
The easiest thing for you to do is to modify haar to use logical indexing on val:
function val = haar(x)
val = zeros(size(x)); % assume zero
val(0<=x & x<0.5) = 1; % set ones
val(0.5<=x & x<1) = -1; % set -1s
end
  1 comentario
R yan
R yan el 3 de Feb. de 2015
thank you. it works fine.
Can I write the same using symbolic?? I tried using symfun but dont know how to write the IF-else part.
thanks

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