Splitting n by 1 matrix

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okoth ochola
okoth ochola el 18 de Jul. de 2022
Editada: Stephen23 el 18 de Jul. de 2022
Hi, I have n by 1 matrix, I want to splitt this matrix into systematically into several smaller matrices of the same dimension. For example let A=transpose([1:1:12552), I want to make other matrices of (24 by 1) from the A. Is there a short command I can use? I have tried 'mat2cell' function but it returns error. Is there something am missing?

Respuesta aceptada

Stephen23
Stephen23 el 18 de Jul. de 2022
Editada: Stephen23 el 18 de Jul. de 2022
A = transpose(1:12552);
C = num2cell(reshape(A,24,[]),1)
C = 1×523 cell array
{24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 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double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double}
You can eaily access the content of the cell array C using indexing, e.g. the second cell:
C{2}
ans = 24×1
25 26 27 28 29 30 31 32 33 34
  4 comentarios
okoth ochola
okoth ochola el 18 de Jul. de 2022
It worked, thank you so much
Stephen23
Stephen23 el 18 de Jul. de 2022
Editada: Stephen23 el 18 de Jul. de 2022
" Is there a fucntion that I can use to calculate mean of each submatrix within C, so as to end up with 523 by 1 matrix?"
The simple and efficient MATLAB approach would avoid the cell array:
A = transpose(1:12552);
B = mean(reshape(A,24,[]),1).'
B = 523×1
12.5000 36.5000 60.5000 84.5000 108.5000 132.5000 156.5000 180.5000 204.5000 228.5000

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