Hello
I have many of array.
do you have any function for instead this CY.
CY = [cy(:,:,1) cy(:,:,2) cy(:,:,3) cy(:,:,4) cy(:,:,5) cy(:,:,6) cy(:,:,7) cy(:,:,8) cy(:,:,9) cy(:,:,10) cy(:,:,11) cy(:,:,12) cy(:,:,13) cy(:,:,14) cy(:,:,15) cy(:,:,16) cy(:,:,17) cy(:,:,18) cy(:,:,19) cy(:,:,20) cy(:,:,21) cy(:,:,22) cy(:,:,23) cy(:,:,24) cy(:,:,25) cy(:,:,26) cy(:,:,27) ... cy(:,:,3000];

 Respuesta aceptada

Hayden Raabe-Garmon
Hayden Raabe-Garmon el 18 de Jul. de 2022
Editada: Hayden Raabe-Garmon el 18 de Jul. de 2022

0 votos

cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
CY=squeeze(cy)'
CY =
1 2 3

3 comentarios

Hayden Raabe-Garmon
Hayden Raabe-Garmon el 18 de Jul. de 2022
This would not be a Cell Array, this is a vector. A Cell/Cell Array is an entirely different class of variables
Mingde
Mingde el 18 de Jul. de 2022
Thank you
Mingde
Mingde el 18 de Jul. de 2022
Thank you. it is working.

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Más respuestas (1)

Image Analyst
Image Analyst el 18 de Jul. de 2022

0 votos

Trust me, you don't want a cell array. I highly doubt it. It uses way more memory and is inefficient. You want code like @Hayden Raabe-Garmon gave you
CY=squeeze(cy)'
If you think you want a cell array, give justification (so I can talk you out of it).

3 comentarios

Mingde
Mingde el 18 de Jul. de 2022
Thank you. it is working.
Mingde
Mingde el 19 de Jul. de 2022
Editada: Mingde el 19 de Jul. de 2022
cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
cy(:,:,4)=4
cy(:,:,5)=5
cy(:,:,6)=6
cy(:,:,7)=7
cy(:,:,8)=8
cy(:,:,9)=9
...
cy(:,:,100)=100
How Can I use loop for mean each 3 cell array?
For example
mean(A)
cy(:,:,1)=1
cy(:,:,2)=2
cy(:,:,3)=3
mean(B)
cy(:,:,4)=4
cy(:,:,5)=5
cy(:,:,6)=6
...
mean(Z)
cy(:,:,98)=98
cy(:,:,99)=99
cy(:,:,100)=100
Image Analyst
Image Analyst el 19 de Jul. de 2022
Again, we're not using cell arrays. And I don't know what range A, B, etc. cover. Do you just want the average of every group of 3 planes/slices? Like
A = cy(:, :, 1:3);
theMean = mean(A, 'all');

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el 18 de Jul. de 2022

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el 19 de Jul. de 2022

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