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Obtain variable name in TLC

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Alexander Sinn
Alexander Sinn el 22 de Jul. de 2022
Comentada: Alexander Sinn el 25 de Jul. de 2022
I am creating a TLC file for my S-Function and I would like to produce c-code to determine the size of my vector-output-signal array via the sizeof function.
However, both LibBlockInputSignalAddr(0, "", "", 0) and LibBlockInputSignal(0, "", "", 0) only return a reference to the first element of the output signal, thus, sizeof will only return the size of one element of the corrsponding array:
sizeof testModel_Y.Outport[0]
Instead I would like to achieve:
sizeof testModel_Y.Outport
Is it possible generate this statement using a TLC file?

Respuesta aceptada

Andy Bartlett
Andy Bartlett el 22 de Jul. de 2022
Consider doing it in two parts
bytes = LibBlockInputSignalWidth(0) * sizeof( LibBlockInputSignal(0, "", "", 0) )
  1 comentario
Alexander Sinn
Alexander Sinn el 25 de Jul. de 2022
Thank you for the answer.This is the workaround I am currently using.
I was hoping to eliminate the multiplication but this seems not to be possible.

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Más respuestas (1)

Walter Roberson
Walter Roberson el 25 de Jul. de 2022
In C,
sizeof testModel_Y.Outport
is the size of the pointer contained in testModel_Y.Outport . Multiplying the size of one element by the number of elements is the standard way to measure size of an array in C.
  1 comentario
Alexander Sinn
Alexander Sinn el 25 de Jul. de 2022
According to https://docs.microsoft.com/en-us/cpp/c-language/sizeof-operator-c?view=msvc-170 above code would return the size of the array instead of the pointer: When you apply the sizeof operator to an array identifier, the result is the size of the entire array rather than the size of the pointer represented by the array identifier.
This is also in accord with my testing of this operator.

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