how to identify rows and columns of a random array with a undetermind amont of rows or colloms

_______BEGINING OF CODE___________________

 n=0

while n<5 || n>25

      n=input('please enter a value 5<n<25---');

      if n<5 || n>25
          disp('the value isnt vaild,try again');
      end

end
array=round(100*rand(n,n))
total_sum=0;

________END OF CODE________________

so basically if I wanted to find the sum of say row 2, how can I declare row 2 as B? so that row "n" can be the equivalent of its place in the alphabet.. example Row1=a Row2=b Row3=c exc... and column1=aa column2=bb exc..

Answer 1

[Hikaru]

I'm just stating my opinion here. But, do you really need to name the rows and columns as specific variables? Isn't it more efficient to just use the index? For example, if you want the user to input which row they are interested in finding the sum of, then:

sum(array(k,:)) % where k is any number indicating the row

Answer 2

[fred brunn]

___CODE_____

clc;

clear;

n=0

while n<5 n>25

    n=input('please enter a value 5<n<25---');

    if n<5 || n>25
        disp('the value isnt vaild,try again');
    end

end array=round(100*rand(n,n))

%find the sum to any row row_number=input('to find the sum of any row please enter a row number') ROW_SUM=sum(array(row_number,:)) fprintf('sum of row selected is---%f\n',ROW_SUM)

%find the collum to any row collum_number=input('to find the sum of any collum please enter a row number') COLLUM_SUM=sum(array(:,collum_number)) fprintf('sum of row selected is---%f\n',COLLUM_SUM)

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worked great thanks for the advice :)