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working on a bisection code and im pretty lost is it right so far?

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adriana resendez
adriana resendez el 25 de Feb. de 2015
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
function [xr ea iter] = bisect(func,x1, xu, es, maxit)
if func(x1)*func(xu)>=0, error('no sign change'); end
xold = x1;
for iter=1:maxit
xr = ???
test = func(x1)*func(xr)
ea = abs((xr-xold)/xr)*100;
if test<0, xu = xr;
elseif test>0; ???;
else ea = 0;
end
  2 comentarios
John D'Errico
John D'Errico el 25 de Feb. de 2015
Please use the code formatting button "{} Code" when you post code. Your code is unreadable as it is.
John D'Errico
John D'Errico el 25 de Feb. de 2015
Editada: John D'Errico el 25 de Feb. de 2015
Having fixed your code (I'll do that once) to make it readable...
Is it right? Of course not.
You have assignments like
xr = ???
and
???;
That last was a good one, though not truly valid syntax. I'll admit that when I stop writing code to take a rest, I usually add a random line like
jw56ywykmej
This way I cannot miss finding it when I resume work later on. At the very least, mlint will tell me about it.
Your code is missing end statements. Lots of other issues I could pick at. For example, why use a for loop instead of a while loop? A for loop forces the code to run for maxit iterations. What if it has converged before then? Yes, this last is a minor issue that relates to efficiency, instead of does the code work.
Essentially, you are going in a reasonable direction, but you are not there yet. So why not finish writing it? Try it out? Learn to debug your code, so learn to use the debugger.

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