MATLAB CODE FOR ROOT MEAN SQUARED

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Grace
Grace el 13 de Sept. de 2022
Editada: Torsten el 13 de Sept. de 2022
Hello,please I have a matrix M, containng three distinct sets of data, and I intend to calculate the root mean squared. Coiuld some kinndly assist me; here is my trial code
clear all;close all;clc
A=[2 4 7 10 28]; %first
B=[1 3.6 8 11 27];%seccond
C=[0.5 5 9.5 13 32];%third
M=[A' B' C'];
[rows, columns] = size(M);
MEAN=zeros(rows, columns);
for row = 1 : rows
MEAN(row) = mean(M(row, :));
cal_rms=sqrt((MEAN-M(row, :)).^2./columns);
end
plot(cal_rms);

Respuesta aceptada

Torsten
Torsten el 13 de Sept. de 2022
This is not the standard definition for the root-mean-square value of a matrix.
Are you sure about the formula ? Then use
cal_rms(row) = sqrt((MEAN-M(row, :)).^2./columns);
instead of
cal_rms=sqrt((MEAN-M(row, :)).^2./columns);
  2 comentarios
Grace
Grace el 13 de Sept. de 2022
Hi Torsten, It does not work, still woth
cal_rms(row) = sqrt((MEAN-M(row, :)).^2./columns);
Torsten
Torsten el 13 de Sept. de 2022
Editada: Torsten el 13 de Sept. de 2022
MATLAB has a function "rms" for the rooot-mean-square value - you might want to use it, but it doesn't work with the matrix elements shifted by the mean value.
What you calculate is some kind of standard deviation of the rows of M, but in this case, you had to divide by (columns-1), not by (columns).
A=[2 4 7 10 28]; %first
B=[1 3.6 8 11 27];%seccond
C=[0.5 5 9.5 13 32];%third
M=[A.', B.', C.'];
[rows, columns] = size(M);
MEAN=zeros(rows,1);
for row = 1 : rows
MEAN(row) = mean(M(row, :));
cal_rms(row) = sqrt(sum((MEAN(row)-M(row,:)).^2)/columns);
end
plot(cal_rms)

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Bruno Luong
Bruno Luong el 13 de Sept. de 2022
Editada: Bruno Luong el 13 de Sept. de 2022
To my book the mean should not be removed in calculation of RMS
M = rand(3,100);
[rows, columns] = size(M);
cal_rms = zeros(rows,1);
for row=1:size(M,1)
cal_rms(row) = sqrt( sum(M(row, :).^2) / columns );
end
cal_rms % theoretical value is sqrt(1/3) for rand()
cal_rms = 3×1
0.5737 0.5854 0.5894

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