# Creating a table by extracting rows from a table based off their values in relation to another table of a different size.

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Low Kay Tong on 15 Sep 2022
Edited: Low Kay Tong on 15 Sep 2022
I have two tables of different size, for example, I have a 16x4 table with headers a,b,c and d and I have another 6x2 table with headers c and d. I have constructed both tables in matlab
a = [11;33;55;77;99;23;45;67;89;87;65;43;10;1;3;5];
b = [22;44;66;88;12;34;56;78;98;76;54;32;21;2;4;6];
c = [2;2;2;2;4;4;4;4;6;6;6;6;8;8;8;8];
d = [2;4;6;8;2;4;6;8;2;4;6;8;2;4;6;8];
T1 = table(a,b,c,d)
cc = [1.2;1.6;5.5;6.7;5.9;2.3];
dd = [2.5;4.6;3.5;3.2;1.5;1.9];
T2 = table(cc,dd)
T3 = T1(abs(T1.c-T2.cc)<=1 & abs(T1.d-T2.dd)<=1)
I wish to construct another table by filtering out rows based on values of abs(c - cc) <= 1 and abs(d - dd)<= 1 as the conditions and construct a new table using the extracted rows. looking like this in due to the order of the previous table t2:
.
But I couldn't do it as the number of variables are different. Any help will be appreciated!
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### Answers (1)

Stephen23 on 15 Sep 2022
a = [11;33;55;77;99;23;45;67;89;87;65;43;10;1;3;5];
b = [22;44;66;88;12;34;56;78;98;76;54;32;21;2;4;6];
c = [2;2;2;2;4;4;4;4;6;6;6;6;8;8;8;8];
d = [2;4;6;8;2;4;6;8;2;4;6;8;2;4;6;8];
T1 = table(a,b,c,d)
T1 = 16×4 table
a b c d __ __ _ _ 11 22 2 2 33 44 2 4 55 66 2 6 77 88 2 8 99 12 4 2 23 34 4 4 45 56 4 6 67 78 4 8 89 98 6 2 87 76 6 4 65 54 6 6 43 32 6 8 10 21 8 2 1 2 8 4 3 4 8 6 5 6 8 8
cc = [1.2;1.6;5.5;6.7;5.9;2.3];
dd = [2.5;4.6;3.5;3.2;1.5;1.9];
T2 = table(cc,dd)
T2 = 6×2 table
cc dd ___ ___ 1.2 2.5 1.6 4.6 5.5 3.5 6.7 3.2 5.9 1.5 2.3 1.9
ixc = any((T1.c-reshape(T2.cc,1,1,[]))<=1,3);
ixd = any((T1.d-reshape(T2.dd,1,1,[]))<=1,3);
T3 = T1(ixc&ixd,:)
T3 = 6×4 table
a b c d __ __ _ _ 11 22 2 2 33 44 2 4 99 12 4 2 23 34 4 4 89 98 6 2 87 76 6 4
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Low Kay Tong on 15 Sep 2022
I am sorry, but your output is different from my intended output. is it due to the lack of the absolute sign? I'd appreciate it if you could explain the code!

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