How to terminate the MATLAB code?
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Noor Fatima
el 23 de Sept. de 2022
Comentada: Walter Roberson
el 23 de Sept. de 2022
I'm running the following code
n = 10000000;
a = 3.8;
x(1) = 0.5;
tic
for i=1:n
x(i+1)=a*x(i)*(1-x(i));
end
Time = toc
I wanted to set some time limit say Time = 35 s.
How can I apply time limit condition on the above code such that if Time= 35 s. The code will automatically terminate.
1 comentario
Sharmin Kibria
el 23 de Sept. de 2022
You can move Time=toc inside the loop and break if (Time == 35) .
Respuesta aceptada
Davide Masiello
el 23 de Sept. de 2022
n = 100000000;
a = 3.8;
x(1) = 0.5;
tic
Time = 0;
for i=1:n
if Time > 5
fprintf('You run out of time')
break
end
x(i+1)=a*x(i)*(1-x(i));
Time = toc;
end
disp(Time)
2 comentarios
Walter Roberson
el 23 de Sept. de 2022
In order to impose a time limit on a calculation without the cooperation of the code, you have to use parfeval() to run the code in a parallel pool or in a background thread pool; you can cancel() the "future" of the worker if it reaches the time limit.
Background pools were introduced relatively recently and do not require additional toolboxes. Parallel pools are older but require Parallel Computing Toolbox
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