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change cell dimension

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Rusmaya Luthfina
Rusmaya Luthfina el 13 de Oct. de 2011
Comentada: Javier el 17 de Nov. de 2020
hi all y teachers,
i have a cell :
a = {{8x1cell} {14x1cell} {11x1cell} {23x1cell} {17x1cell} {8x1cell} {18x1cell} {14x1cell} {20x1cell} {28x1cell}}
i need to change the dimension of each cell to a fix number, say 50x1 cell. So each cell will have dimension 50x1, and i want the rest rows of the cell to be 0 or []
ex: take the 1st col of the cell, it's 8x1cell and i need it to be 50x1 with 42rows left to be zero or []
old 8x1cell = {'i'; 'need'; 'a'; 'glass'; 'of'; 'water'; 'right'; 'now'}
new 8x1cell = {{'i'; 'need'; 'a'; 'glass'; 'of'; 'water'; 'right'; 'now'; 0; 0; ... till row 50}
is there any possible way i can perform that? really need your helps, plzz! :(
thx,
Maya

Respuesta aceptada

Fangjun Jiang
Fangjun Jiang el 13 de Oct. de 2011
for k=1:length(a)
a{k}(end+1:50={[]}; %pad with []
%a{k}(end+1:50={0}; %pad with []
end

Más respuestas (2)

Jan
Jan el 13 de Oct. de 2011
for k=1:length(a)
L = length(a{k});
a{k}(L+1:50) = {0};
end
  1 comentario
Javier
Javier el 17 de Nov. de 2020
Hello there, lets say I have the cell array
1×6 cell array
{8791×1 double} {8782×1 double} {8802×1 double} {8795×1 double} {8806×1 double} {8791×1 double}
I need to change all of them to be
{8782×1 double}
So that I would have a 1×6 cell array where there is repeated {8782×1 double}

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Rusmaya Luthfina
Rusmaya Luthfina el 14 de Oct. de 2011
Wuaaaaa,, its work! the answers you both give me are working exactly what i need,, i've just checked and it's so simple,, stupid me. sorry for bothering you with this low-level question.. :D
So many thanks for you Mr Simon and Mr Jiang.
Ouw,, may i asked 1 more low-level question?
Is it possible to make that cell array (a) as output in a function?? 'coz i need to call a function containing that cell as an output..
---Maya----
  5 comentarios
Rusmaya Luthfina
Rusmaya Luthfina el 17 de Oct. de 2011
i've already figure this out,, :D thx
Alexander Sidelev
Alexander Sidelev el 3 de Abr. de 2018
What is the solution to your problem? I can't figure it out

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