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How to add tolerance to iteration with if statement

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Bethany Sinclair
Bethany Sinclair el 27 de Oct. de 2022
Respondida: Chunru el 27 de Oct. de 2022
I have a Gauss-seidel iteration code, which works to 99 iterations with a relaxation factor. However, when I put an if statement in (no other changes), to say if the different between iteration a^x+1-a^x is less than a certain tolerance say 0.1 then stop the iteration sequence before the specified 99 iterations.
Any help to spot any issues would be appreciated!
a2(1,1)=0;
b2(1,1)=0;
c2(1,1)=0;
R2=0.3;
for i=1:99
if a2(i+1,1)-a2(i,1)<0.1
a2(i+1,1)=(1-R2)*a2(i,1)+R2*(4-b2(i,1)-c2(i,1));
b2(i+1,1)=(1-R2)*b2(i,1)+R2*(2*a2(i+1,1)+4*c2(i,1)-33)/3;
c2(i+1,1)=(1-R2)*c2(i,1)+R2*(3*a2(i+1,1)-2*b2(i+1,1)-2)/2;
end
end
figure(5);
plot(a1);
hold on
plot (b1);
plot (c1);

Respuesta aceptada

Chunru
Chunru el 27 de Oct. de 2022
x(1,1)=0; %Initial guess, x=0
y(1,1)=0; %Initial guess, y=0
z(1,1)=0; %Initial guess, z=0
R=0.3; %relaxation factor
for i=1:99 %99 is the number of iterations
x(i+1,1)=(1-R)*x(i,1)+R*(4-y(i,1)-z(i,1)); %what multiplied with R is the "new" x value produced by the equation
y(i+1,1)=(1-R)*y(i,1)+R*(2*x(i,1)+4*z(i,1)-33)/3; %what multiplied with R is the "new" y value produced by the equation
z(i+1,1)=(1-R)*z(i,1)+R*(3*x(i,1)-2*y(i,1)-2)/2; %what multiplied with R is the "new" z value produced by the equation
if abs(x(i+1)-x(i)) < 0.1
break
end
end
plot(x);
hold on
plot(y);
plot(z);

Más respuestas (1)

Chunru
Chunru el 27 de Oct. de 2022
% if a2(i+1,1)-a2(i,1)<0.1
% change the above to:
if abs(a2(i+1,1)-a2(i,1))<0.1
  3 comentarios
Chunru
Chunru el 27 de Oct. de 2022
Not sure what algo you want to implement. Can you describe it?
Bethany Sinclair
Bethany Sinclair el 27 de Oct. de 2022
Below is a code for iteration to find 3 values of a simulteneous equation to 99 iterations. I want to be able to stop the iteration algorithm early (before the 99 iterations are up) if the results fal within a certain tolerance. I.e - the result for A is within 0.1 of the previous iteration. The code below works, it just doesn't like it when I put the if statement in?
x(1,1)=0; %Initial guess, x=0
y(1,1)=0; %Initial guess, y=0
z(1,1)=0; %Initial guess, z=0
R=0.3; %relaxation factor
for i=1:99 %99 is the number of iterations
x(i+1,1)=(1-R)*x(i,1)+R*(4-y(i,1)-z(i,1)); %what multiplied with R is the "new" x value produced by the equation
y(i+1,1)=(1-R)*y(i,1)+R*(2*x(i,1)+4*z(i,1)-33)/3; %what multiplied with R is the "new" y value produced by the equation
z(i+1,1)=(1-R)*z(i,1)+R*(3*x(i,1)-2*y(i,1)-2)/2; %what multiplied with R is the "new" z value produced by the equation
end
plot(x);
hold on
plot(y);
plot(z);

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