how to add zeros in fronts of any number in matrix

dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
i want to add zeros in front of 1, 2, 3, 4, 5, 6, 7, 8, 9 like this 01, 02, 03, 04, 05, 06, 07, 08, 09 in months and days matrix. how will do this. please help me. thank you in advance.

 Respuesta aceptada

Konstantinos Sofos
Konstantinos Sofos el 22 de Mzo. de 2015
Editada: Konstantinos Sofos el 22 de Mzo. de 2015
Asking for this probably you do not want anymore your years, months, days vectors to be numbers but chars. Because you know from basic maths that '01' doesn't exist as type of number.
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false)
In the same logic you could reform days and years
Regards

5 comentarios

Konstantinos Sofos
Konstantinos Sofos el 22 de Mzo. de 2015
Editada: Konstantinos Sofos el 22 de Mzo. de 2015
After your comment you could use the above as
filename1 = ['3B42_daily.',myCellYears{i},'.',myCellMonth{i},'.',myCellDay{i},'.7.SUB.nc']
And as an example if i = 1
filename1 = ['3B42_daily.',myCellyears{1},'.',myCellMonth{1},'.',myCelldays{1},'.7.SUB.nc']
will give you as result
filename1 =
3B42_daily.1998.01.01.7.SUB.nc
devendra
devendra el 22 de Mzo. de 2015
Editada: devendra el 22 de Mzo. de 2015
thank you so much Konstantinos Sofos this is helping alot but can we remove ' ' (inverted commas) from this because this is giving this type of output.
'01'
'01'
'01'
dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
%DAYS
myCellDay = cellfun(@(x) num2str(x),num2cell(days),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellDay);
idx = idx==1;
myCellDay(idx) = cellfun(@(x) strcat('0', x),myCellDay(idx),'UniformOutput', false);
%MONTHS
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false);
% YEARS
myCellYears = cellfun(@(x) num2str(x),num2cell(years),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellYears);
idx = idx==1;
myCellYears(idx) = cellfun(@(x) strcat('0', x),myCellYears(idx),'UniformOutput', false);
for i = 1:numel(M(:,1))
filename = ['3B42_daily.',myCellYears{i},'.',myCellMonth{i},'.',myCellDay{i},'.7.SUB.nc']
end
for the ' ' (inverted commas) use {} instead of () to read the context of a char cell array as i showed above. Hope that this helps.
devendra
devendra el 22 de Mzo. de 2015
thank you so much Konstantinos Sofos for helping me.

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Más respuestas (1)

Jan
Jan el 22 de Mzo. de 2015
sprintf and also num2str can use the '%02d' format:
myCellMonth = cellfun(@(x) num2str(x, '%02d'), num2cell(months),'UniformOutput', false);
This inserts a leading zero, when the number has less than 2 digits. Instead of preparing cell strings, you can use sprintf directly:
for i = 1:numel(M(:,1))
filename = sprintf('3B42_daily.%04d.%02d.%02d.7.SUB.nc', year(i), month(i), day(i));
...
end

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el 22 de Mzo. de 2015

Respondida:

Jan
el 22 de Mzo. de 2015

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