dimension mismatch??! i cant see how this can be a dimension mismatch?

A.textdata(:,3) holds a large set of dates
I am trying to do this:
for i=1:size(A.textdata)
Dates(i,1) = datenum(A.textdata(i,3),'dd-mm-yyyy HH:MM:SS');
Dates2(i,1) = datestr(Dates(i,1),'dd-mm-yyyy ')
end
but i am getting thins error:
> ??? Subscripted assignment dimension mismatch.
Error in ==> Load at 12 Dates2(i,1) = datestr(Dates(i,1),'dd-mm-yyyy ')
Why is that? i cant see how there can be any dimension mismatches??

 Respuesta aceptada

The problem is that
Dates2(i,1)
is a scalar, but
datestr(Dates(i,1),'dd-mm-yyyy ')
returns a string with length 10.
Dates2(i,:) = datestr(Dates(i,1),'dd-mm-yyyy ');
should work.

Más respuestas (0)

Categorías

Más información sobre Operators and Elementary Operations en Centro de ayuda y File Exchange.

Preguntada:

el 19 de Oct. de 2011

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by