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Trying to make an Adams-Bashforth method with Richardson error estimate

1 visualización (últimos 30 días)
ce
ce el 10 de Dic. de 2022
Editada: Mayank Sengar el 12 de En. de 2023
%This program solves the initial value problem
% y' = f(x,y), x0 <= x<= b, y(x0)=y0
%Initializing vaiables
%f'(x,y)=
f = @(x,y) cos(y).^2; %derivative in question
g = @(x) atan(x); %this is the actual solution
x0 = 0; %initial value of x
x_end = 10; %end of approximation
h = 0.1; %size of decimal place (0.1,0.001,etc
y0=0; %initial value of y
n = fix((x_end-x0)/h)+1;
x = linspace(x0,x_end,n);
y = zeros(n,1);
y(1) = y0;
f1 = f(x(1),y(1));
y(2) = y(1)+h*f1;
%need to add error
for i = 3:n
f2 = f(x(i-1),y(i-1));
y(i) = y(i-1)+h*(3*f2-f1)/2;
f1 = f2;
fprintf('%5.4f %11.8f\n', x(i), y(i));
plot(x(i),y(i),'b.'); grid on;
fplot(g,[x0,x_end]);
xlabel('x values'); ylabel('y values');
hold on;
end
I'm not sure how I would add the Richardson error to this code. I see the formula in my textbook, but don't understand how I would make it work. . Like I don't really know what that means. I understand the AB method for solving DefEqs, but not ther errors
  1 comentario
Torsten
Torsten el 10 de Dic. de 2022
Editada: Torsten el 10 de Dic. de 2022
I'm confident that after reading this article
you will know how Richardson extrapolation works.

Iniciar sesión para comentar.

Respuestas (1)

Mayank Sengar
Mayank Sengar el 12 de En. de 2023
Editada: Mayank Sengar el 12 de En. de 2023

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