How to plot the surface of an arbitrary given TABLE (not matrix) with X,Y,Z values?

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I want to plot the surface Z of arbitrary given values for each X,Y-pair.
I usually IMPORT the tables with the X,Y,Z data, so I they are not a matrix.
An example is displayed below:
1 1 0.171121066356432
1 2 0.0326008205305280
1 3 0.561199792709660
2 1 0.881866500451810
2 2 0.669175304534394
2 3 0.190433267179954
3 1 0.368916546063895
3 2 0.460725937260412
3 3 0.981637950970750
I tried the following lines to plot the surface
[X,Y] = meshgrid(1:1:3, 1:1:3);
But I get the following error:
??? Error using ==> surf at 78
Z must be a matrix, not a scalar or vector.
Error in ==> Untitled2 at 5
Question: I replaced the x,y coordinate with the function meshgrid but what do I make wih the Z values?
I'm aware that Z is not a matrix, but this is exactly the problem!!!
I hope someone knows how to correct these commands

Accepted Answer

Walter Roberson
Walter Roberson on 20 Oct 2011
[ux, ax, bx] = unique(YourTable(:,1));
[uy, ay, by] = unique(YourTable(:,2));
[X, Y] = ndgrid(ux, uy);
Z = accumarray( [bx(:),by(:)], YourTable(:,3), [], NaN );
This code will even average the z entries if there are multiple (x,y) pairs with different z.
If I have done it right, it does not need to be fed non-negative integers in the first two table columns.
I set the code up so that if there is some combination of (x,y) for which there is no table value, then NaN will be inserted as the Z value. surf() understands NaN as meaning not to plot that square. But you could put any other fixed value numeric there instead. In particular, in the special case where you want 0 for missing values, you can abbreviate the accumarray call to
Z = accumarray( [bx(:),by(:)], YourTable(:,3) );

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More Answers (1)

Jan on 20 Oct 2011
You can reshape Z such that it becomes a matrix:
[X,Y] = meshgrid(1:1:3, 1:1:3);
Z = reshape(rand(9, 1), 3, 3);
surf(X, Y, Z)
Of course you would use "rand(3,3)" in a real application.
  1 Comment
Emerson De Souza
Emerson De Souza on 21 Oct 2011
Thank you Jan,
your suggestion works as long the length of X and Y are identical which must not be the case for real applications.
For the case that X and Y have different length I used the method suggested by Walter.
But thank you again for your attention

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