Borrar filtros
Borrar filtros

How can I get a variable that starts in t=0?

5 visualizaciones (últimos 30 días)
Amelie
Amelie el 21 de Feb. de 2023
Comentada: Amelie el 21 de Feb. de 2023
Dear all,
I am trying to get an index for the variable y that starts at 500 in t=0 and is carried forward from period t=1 onwards by multiplying the variable y with ins_urz. In other words, I am trying to set a starting value for the variable y of 500 in t=0, and then multiply it by ins_urz from period t=1 onwards, in order to use the result of the multiplication in the respective period to multiply it by the continuous elements of ins_urz.
for t=0:249
y(1,1)=500;
y(t+1,:)=y(t,1).*ins_urz(t+1,:);
end
Unfortunately, this has not worked so far, because I get the error message "Index in position 1 is invalid. Array indices must be positive integers or logical values" every time I try.
Can someone help me how to insert the index correctly into the codes?
Thanks a lot for your help!

Respuesta aceptada

Torsten
Torsten el 21 de Feb. de 2023
y = cumprod([500;ins_urz])
  4 comentarios
Torsten
Torsten el 21 de Feb. de 2023
ins_urz is a (250,1) vector
Then the line of code will do what you want.
Amelie
Amelie el 21 de Feb. de 2023
Thank you!

Iniciar sesión para comentar.

Más respuestas (1)

Jan
Jan el 21 de Feb. de 2023
Editada: Jan el 21 de Feb. de 2023
y(1, 1) = 500; % Set initial value before the loop
for t = 1:249 % y(1, :) is defined already, so start at t=1, not t=0
y(t+1, :) = y(t, 1) * ins_urz(t+1, :);
end
  1 comentario
Amelie
Amelie el 21 de Feb. de 2023
Now it works!
Thank you very much, that was very helpful!

Iniciar sesión para comentar.

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by