Hello dear forum:
I am working on an battary optimization problem. As part of the problem, an electrical resistance should be dependent on T, C-Rate and SOC. I have a lot of sample values in between which it should be interpolated. Because the optimization problem is designed as a shortest path model, it iterates around 200 million times. My current approach is shown below and is currently very slow due to the interpolation. I used the griddata-command for interpolation.
Is there a faster way? My ideas:
  • Interpolate a lot of values in the first rotation and then only select the closest one etc.
  • Turn the sample values into a function. (I have heard about this but didnt find it).
I am glad for any suggestions!
Thank you and merry easter.
Here my current function:
function R = calculateResistance_neu_neu(R0,I,SOC,T,Q)
T = T;
C_Rate = I/Q;
SOC = SOC;
matrix = [5, 0.5, 0.1, 2.25, 135;
.....
45, 3, 0.8, 1, 60;
45, 3, 0.9, 1, 60];
Multiplikator = griddata(matrix(:,1),matrix(:,2),matrix(:,3),matrix(:,4),T,C_Rate,SOC);
R = R0*Multiplikator;

4 comentarios

埃博拉酱
埃博拉酱 el 9 de Abr. de 2023
Try to set the matrix as persistent. You'd better show more code outside this function. Optimization is hardly possible without your outer code.
Fabian Haslwanter
Fabian Haslwanter el 9 de Abr. de 2023
Thank you. Tried making it persistent. However most of the time is consumed by the interpolation.
Here is the full code. I tried to put in some comments to explain it but it bases on the shortest path method. I hope it's somewhat understandable.
Matt J
Matt J el 9 de Abr. de 2023
Your mfile contains no function called calculateResistance_neu_neu()
Fabian Haslwanter
Fabian Haslwanter el 9 de Abr. de 2023
Editada: Fabian Haslwanter el 9 de Abr. de 2023
Line 47
I just tried running it and it works for me. Here again with the function. Hope thats what you mean :)
EDIT: Sorry i should have mentioned i have the function in a different file...

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 Respuesta aceptada

Vanshika Vaishnav
Vanshika Vaishnav el 12 de Abr. de 2023

0 votos

Setting the matrix as persistent will resolve the issue, however most of the time will be consumed by the interpolation.

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