solving complex matrix with symbolic variables

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ZENONG
ZENONG el 22 de Jun. de 2023
Respondida: Torsten el 22 de Jun. de 2023
hello, I am trying to solve a complex matrix with symbols, but it returns''Empty sym: 0-by-1''. I would like to know why this happened and how could I solve this problem. Thank you.
  1 comentario
ZENONG
ZENONG el 22 de Jun. de 2023
Hi, I updated my code, and it retured values, but I believe there still are some errors, maybe the ''theta'' and ''abs'' variables?

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Respuesta aceptada

Vishnu
Vishnu el 22 de Jun. de 2023
Hi Zenong,
From the code, it seems that you are trying to solve the complex matrix equations using symbolic variables.However, the issue is that the variables used for 'VI' and 'Vscl' are not symbolic variables, and this is causing the error "Empty sym: 0-by-1".
To solve this issue, the you need to define symbolic variables 'p1', 'q1', 'p2', 'q2', 'p3', 'q3', 'p4' and 'q4' using 'syms' function.
syms a b c d e f g h k p1 p2 p3 p4 q1 q2 q3 q4
Here is the modified code:
syms a b c d e f g h k real %defining symbolic variables
z1=-30j;
z2=0.08+0.40j;
z3=-35j;
z4=0.10+0.50j;
z5=0.10+0.50j;
z6=-25j;
z7=0.30j;
p1=a;
p2=0.55;
p3=0.30;
p4=0.50;
q1=1j*b;
q2=0.15j;
q3=0.201j;
q4=1j*c;
e1=1.05;
e2=d;
e3=e;
e4=f;
f1=0j;
f2=1j*g;
f3=1j*h;
f4=1j*k;
y11=1/z1+1/z2+1/z5;
y12=(-1)*1/z2;
y13=(-1)*1/z5;
y14=0;
y21=y12;
y22=1/z2+1/z4+1/z3;
y23=(-1)*1/z4;
y24=0;
y31=y13;
y32=y23;
y33=1/z6+1/z7+1/z5+1/z4;
y34=0;
y41=y14;
y42=y24;
y43=y34;
y44=1/z7;
Y=[y11,y12,y13,y14;
y21,y22,y23,y24;
y31,y32,y33,y34;
y41,y42,y43,y44];
conjY=conj(Y); %conjugate Y
V=[e1+f1;e2+f2;e3+f3;e4+f4];
format shortG
conjY=round(conjY,2,'significant') %conjugate Y
Vscl=diag(V) %scalar matrix V
conjV=conj(V) %conjugate V
%Defining symbolic variables
syms a b c d e f g h k p1 p2 p3 p4 q1 q2 q3 q4
[a,b,c,d,e,f,g,h,k] = solve([p1+q1;p2+q2;p3+q3;p4+q4]==Vscl*conjY*conjV,[a,b,c,d,e,f,g,h,k]);

Más respuestas (2)

MANIK
MANIK el 22 de Jun. de 2023
Editada: MANIK el 22 de Jun. de 2023
As per my understanding, you're trying to solve a complex matrix equation in MATLAB
Well, I was going through your code, it is all correct. But, here you're trying to solve a problem, which contains 4 equations and 9 variables which is not possible. That's why you're getting an error here.

Torsten
Torsten el 22 de Jun. de 2023
syms a b c d e f g h k real
z1=-30j;
z2=0.08+0.40j;
z3=-35j;
z4=0.10+0.50j;
z5=0.10+0.50j;
z6=-25j;
z7=0.30j;
p1=a;
p2=-0.55;
p3=-0.30;
p4=0.50;
q1=1j*b;
q2=-0.15j;
q3=-0.20j;
q4=1j*c;
e1=1.05;
e2=d;
e3=e;
e4=f;
f1=0j;
f2=1j*g;
f3=1j*h;
f4=1j*k;
y11=1/z1+1/z2+1/z5;
y12=(-1)*1/z2;
y13=(-1)*1/z5;
y14=0;
y21=y12;
y22=1/z2+1/z4+1/z3;
y23=(-1)*1/z4;
y24=0;
y31=y13;
y32=y23;
y33=1/z6+1/z7+1/z5+1/z4;
y34=(-1)*1/z7;
y41=y14;
y42=y24;
y43=y34;
y44=1/z7;
theta=f^2+k^2;
abs=1.1^2;
Y=[y11,y12,y13,y14;
y21,y22,y23,y24;
y31,y32,y33,y34;
y41,y42,y43,y44];
conjY=conj(Y);
V=[e1+f1;e2+f2;e3+f3;e4+f4];
format shortG
conjY=round(conjY,2,'significant');
Vscl=diag(V);
conjV=conj(V);
VIt=Vscl*conjY*conjV;
P=simplify([real([p1;p2;p3;p4]);imag([q1;q2;q3;q4]);theta])
P = 
Q=simplify([real(VIt);imag(VIt);abs])
Q = 
sol=vpasolve(P==Q)
sol = struct with fields:
a: [4×1 sym] b: [4×1 sym] c: [4×1 sym] d: [4×1 sym] e: [4×1 sym] f: [4×1 sym] g: [4×1 sym] h: [4×1 sym] k: [4×1 sym]
sol.a
ans = 
sol.b
ans = 
sol.c
ans = 
sol.d
ans = 
sol.e
ans = 
sol.f
ans = 
sol.g
ans = 
sol.h
ans = 
sol.k
ans = 
error = arrayfun(@(i)subs(P-Q,[a b c d e f g h k],[sol.a(i) sol.b(i) sol.c(i) sol.d(i) sol.e(i) sol.f(i) sol.g(i) sol.h(i) sol.k(i)]),1:4,'UniformOutput',0)
error = 1×4 cell array
{9×1 sym} {9×1 sym} {9×1 sym} {9×1 sym}
error{1}
ans = 
error{2}
ans = 
error{3}
ans = 
error{4}
ans = 

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