Remove zeros from a vector from a specific position

Hello, I have the following vector as example:

X=[0, 0; 0.02, 2.3;0.04, 0.4; 0, 0; 0.06, 2.5; 0.08, 3.6; 0, 0; 0.10, 2.5]

I want to remove the zeros and I only want to keep the zeros at the beginning and obtain the following matrix:

X=[0, 0; 0.02, 2.3;0.04, 0.4; 0.06, 2.5; 0.08, 3.6; 0.10, 2.5]

I know this option

X( all(~X,2), : ) = [];

which eliminates all the zeros and then I can add the zeros again at the beggining using

X=vertcat([0 0],X);

but there must be a direct way to do it. I would appreciate the help.

[the cyclist]

Will there always be at least one row of zeros at the beginning?

If so, will there always be exactly one row of zeros at the beginning?

[Jorge Luis Paredes Estacio]

Yes, there will be always zeros at the beginning.

Answer 1

[Bruno Luong]

remove = all(~X,2);
remove(1) = false;
X(remove,:) = [];

[Jorge Luis Paredes Estacio]

Thank you.

[Bruno Luong]

One liner

X([false;all(~X(2:end,:),2)],:)=[];

[Jorge Luis Paredes Estacio]

I think something is missing. Thank you.

[Bruno Luong]

Fixed

[Jorge Luis Paredes Estacio]

THANK YOU VERY MUCH. :).

[the cyclist]

FYI, this solution will not work if there are multiple rows of leading zeros to keep. (That's why I asked if there was always exactly one row of leading zeros.) For example,

X = [0, 0;
     0, 0;
     2, 3;
     5, 7;
     0, 0];

X([false;all(~X(2:end,:),2)],:)=[]

X = 3×2

0 0 2 3 5 7