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NONLCON must be a function using lsqnonlin

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James99
James99 el 27 de Ag. de 2023
Comentada: James99 el 28 de Ag. de 2023
Hello everyone!
I am trying to estimate parameters using lsqnonlin and I get the following error:
Error using cnls
NONLCON must be a function
Error in lsqnonlin (line 220)
[xCurrent,Resnorm,FVAL,EXITFLAG,OUTPUT,LAMBDA,JACOB] = cnls(caller, FUN,xCurrent,A,B,Aeq,Beq,LB,UB,NONLCON, ...
I have no nonlinear constraints and therefore I left NONLCON as empty square brackets. I don't understand where I am going wrong.
The error occurs on line 70.

Respuesta aceptada

Matt J
Matt J el 27 de Ag. de 2023
Editada: Matt J el 27 de Ag. de 2023
No, you have set the nonlcon argument to Cexp which is a numeric vector. You should review the documentation for the correct ordering if the arguments.
  6 comentarios
Matt J
Matt J el 28 de Ag. de 2023
If the optimization time is long, it doesn't necessarily mean you have slow convergence. If one execution of resfun takes a long time, that will also make the optimization time longer.
James99
James99 el 28 de Ag. de 2023
Right, but the warnings about not reaching the solution without reducing the time step below a permitted value a part of the process? I noticed that MATLAB continues with the calculation despite of these warnings. I suppose it does that particular iteration with smallest permitted time step value.

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