Creating 'n' matrices with each one with 'n' in its name

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Paul Barrette
Paul Barrette el 17 de Sept. de 2023
Editada: Paul Barrette el 20 de Sept. de 2023
I am building 'n' matrices line by line:
YEAR1 = zeros(DATE_RANGE(1,3));
YEAR2 = zeros(DATE_RANGE(2,3));
YEAR3 = zeros(DATE_RANGE(3,3));
...
To avoid manually entering each line, I would like to use a looping method, e.g.,
for n=1:10
YEARn = zeros(DATE_RANGE(n,3));
end
My searches bring me to the concept of 'dynamic access' (eval), which is not recommended. But am not sure if this applies to my case.
  1 comentario
Stephen23
Stephen23 el 18 de Sept. de 2023
Editada: Stephen23 el 20 de Sept. de 2023
"To avoid manually entering each line, I would like to use a looping method"
That is a good approach. The best approach is to use arrays.
"My searches bring me to the concept of 'dynamic access' (eval)"
That is a very bad approach.
"But am not sure if this applies to my case."
That advice definitely applies to your case. Your approach using dynamic variable names is not recommended: your approach forces you into writing slow, complex, inefficient, obfuscated, buggy code that is hard to debug:
So far there is no obvious reason why you could not just use basic matrices or arrays for your data, just like MATLAB is designed for. If all of those arrays are the same size then a basic 3D array would suffice.
Note that calling ZEROS with one input argument often produces unexpected results.

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Torsten
Torsten el 17 de Sept. de 2023
Movida: Torsten el 17 de Sept. de 2023
YEAR{n} = zeros(DATE_RANGE(n,3));
  2 comentarios
Dyuman Joshi
Dyuman Joshi el 17 de Sept. de 2023
That is, using Cell arrays to store matrices of different sizes.
@Paul Barrette, Using Cell arrays is also the first alternative mentioned in the thread you have linked -
Paul Barrette
Paul Barrette el 20 de Sept. de 2023
Editada: Paul Barrette el 20 de Sept. de 2023
A 3D array, as suggested by @Stephen23, was my first idea, but the arrays are of slightly different size. Cell arrays is the way to go - I've never used them, but now is the time. Thanks all. And sorry for not searching better and not providing adequate explanations (I wil do better next time).

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Walter Roberson
Walter Roberson el 17 de Sept. de 2023
See https://www.mathworks.com/matlabcentral/answers/2020976-i-want-to-store-the-vector-from-each-for-loop-iteration-how-can-i-do-this#answer_1310391 for sample code that iterates through variable names, a, b, c, d, e, ... z, aa, ab, ac, ...

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