Plotting variables of continuously array with different colors

2 visualizaciones (últimos 30 días)
Hello everyone,
Is it possible to :
(1) Change the value of Station column of this array (excel attached) into ordered rank Station? Anyone knows the code to do this? FYI, the number of stations is in hundreds (I put here for example only 3 stations) so, doing this in loop is preferable solution.
(2) Plot those three Station's profile of variable "s" vs depth from those three stations with different colors of line plots? Anyone knows the code to do this also?
Thank you!

Respuesta aceptada

Star Strider
Star Strider el 10 de Oct. de 2023
Editada: Star Strider el 10 de Oct. de 2023
You can use either unique or findgroups for this to get serial indices —
T1 = readtable('datax.xlsx')
T1 = 17×5 table
Station lon lat depth salinity _______ ______ _____ _____ ________ 2 114.64 -8.16 0 33.995 2 114.64 -8.16 2 33.994 2 114.64 -8.16 4 33.994 2 114.64 -8.16 6 33.993 2 114.64 -8.16 8 33.993 2 114.64 -8.16 10 33.992 7 114.72 -8.16 0 33.976 7 114.72 -8.16 2 33.978 7 114.72 -8.16 4 33.977 7 114.72 -8.16 6 33.977 31 114.8 -8.16 0 33.983 31 114.8 -8.16 2 33.981 31 114.8 -8.16 4 33.981 31 114.8 -8.16 6 33.981 31 114.8 -8.16 8 33.981 31 114.8 -8.16 10 33.98
[Us,ix1,ix2] = unique(T1.Station, 'stable');
T1.Station = ix2
T1 = 17×5 table
Station lon lat depth salinity _______ ______ _____ _____ ________ 1 114.64 -8.16 0 33.995 1 114.64 -8.16 2 33.994 1 114.64 -8.16 4 33.994 1 114.64 -8.16 6 33.993 1 114.64 -8.16 8 33.993 1 114.64 -8.16 10 33.992 2 114.72 -8.16 0 33.976 2 114.72 -8.16 2 33.978 2 114.72 -8.16 4 33.977 2 114.72 -8.16 6 33.977 3 114.8 -8.16 0 33.983 3 114.8 -8.16 2 33.981 3 114.8 -8.16 4 33.981 3 114.8 -8.16 6 33.981 3 114.8 -8.16 8 33.981 3 114.8 -8.16 10 33.98
figure
stem3(T1.Station, T1.depth, T1.salinity, ':k', 'Marker','none')
hold on
scatter3(T1.Station, T1.depth, T1.salinity, 150, T1.salinity, 'p', 'filled')
hold off
xlabel('Station')
ylabel('Depth')
zlabel('Salinity')
xticks(1:3)
This uses the third output of unique to get serial indices (note that I use the 'stable' argument to avoid sorting the results). The findgroups function works similarly to produce a grouping variable. The grouping variable vector is used here as the new value for ‘Station’.
EDIT — Added plots.
.
  12 comentarios
Adi Purwandana
Adi Purwandana el 11 de Oct. de 2023
Editada: Adi Purwandana el 11 de Oct. de 2023
I think I solved it...
LON(k,:) = StaData{k}.long(1);
Star Strider
Star Strider el 11 de Oct. de 2023
That is correct.
Actually:
LON = StaData{k}.lon(1);
or:
LON(k) = StaData{k}.lon(1);
depending on the result you want.
(I was away for a few minutes running errands.)

Iniciar sesión para comentar.

Más respuestas (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 10 de Oct. de 2023
Logical indexing would be an easy way of sorting the data and assigning new values to column 'station'. Then use the sorted data indecies to plot the data: s vs. depth
Here is one of the ways of doing it:
F = readmatrix('datax.xlsx');
Idx1=F(:,1)==2;
Idx2=F(:,1)==7;
Idx3=F(:,1)==31;
F(Idx1,1) = 1;
F(Idx2,1) = 2;
F(Idx3,1) = 3;
% Plotting the data
plot(F(Idx1, 5),F(Idx1, 4), '-o','linewidth', 2), hold all
plot(F(Idx2, 5),F(Idx2, 4), '-s','linewidth', 2)
plot(F(Idx3, 5),F(Idx3, 4), '-d','linewidth', 2)
legend('Station: 1', 'Station: 2', 'Station: 3', 'location', 'best')
grid on
xlabel('s')
ylabel('depth')
  1 comentario
Adi Purwandana
Adi Purwandana el 10 de Oct. de 2023
Thank you @Sulaymon Eshkabilov. It's solved if the number of station is not much. In my case, the number of stations is in hundreds and even thousands. Do you know to do that in something like looping lines to do this?

Iniciar sesión para comentar.

Categorías

Más información sobre Resizing and Reshaping Matrices en Help Center y File Exchange.

Productos


Versión

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by