remove DC component of real time signal

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L
L el 14 de Nov. de 2023
Comentada: Star Strider el 14 de Nov. de 2023
I am using a interface for acquiring a signla in matlab.
The signal is sampled at 500Hz. I have to remove the DC component in real time.
How can I do that?
I know that simulink has the DC blocker block, but I need to accomplish this inside a matlab routine!

Respuestas (1)

Star Strider
Star Strider el 14 de Nov. de 2023
The D-C component is the mean of the signal, so for a recorded signal, simply subtract the mean.
Otherwise, since the D-C offsset is defined as having a frequency of zero (rad/s, Hz, or anything else), a highpass filter (or bandpass filter) with its passband (or lower passband) slightly above zero should remove the D-C offset. The resulting signal should then have a zero D-C offset.
  5 comentarios
L
L el 14 de Nov. de 2023
Editada: L el 14 de Nov. de 2023
sampling is 500Hz (2ms). Matlab receives a vector of 10 points at each 20ms. I can save up to 30 samples, if I want.
My signal of interest is actually between 0.25 and 4 hz.
So I could band pass it.. but if I could just remove the DC will also help.
What is important is to keep the signal without any introduced delays.
Star Strider
Star Strider el 14 de Nov. de 2023
This is a difficult filter to realise because the lower transition region is too steep. I can make it work with a lower attenuation (35 dB rather than 50 dB) for ‘Rs’ and then it distorts the filtered signal significantly less. I encourage you to experiment with various passband, stopband, and atttenuation values to get the result you want.
Fs = 500; % Sampling Frequency (Hz)
Fn = Fs/2; % Nyquist Frequency (Hz)
Wp = [0.25 4.0]/Fn; % Passband Frequency (Normalised)
Ws = [0.01 5.0]/Fn; % Stopband Frequency (Normalised)
Rp = 1; % Passband Ripple
Rs = 35; % Passband Ripple (Attenuation)
[n,Wp] = ellipord(Wp,Ws,Rp,Rs); % Elliptic Order Calculation
[z,p,k] = ellip(n,Rp,Rs,Wp); % Elliptic Filter Design: Zero-Pole-Gain
[sos,g] = zp2sos(z,p,k); % Second-Order Section For Stability
figure
freqz(sos, 2^16, Fs) % Filter Bode Plot
set(subplot(2,1,1), 'XLim',[0 10]) % Zoom To Region-Of-Interest
set(subplot(2,1,2), 'XLim',[0 10])
L = 10*30;
t = linspace(0, Fs*L, Fs*L+1).'/Fs;
signal = sum(sin(2*pi*t.*[0.1:0.1:5 10:10:240]),2);
filtered_signal = filtfilt(sos,g,signal);
figure
plot(t, signal, 'DisplayName','Original')
hold on
plot(t, filtered_signal, 'DisplayName','Filtered')
hold off
xlabel('Time (s)')
ylabel('Amplitude')
legend('Location','best')
[FTsignal,Fv] = FFT1(signal, t);
[FTfiltered_signal,Fv] = FFT1(filtered_signal,t);
figure
plot(Fv, abs(FTsignal)*2, 'DisplayName','Original')
hold on
plot(Fv, abs(FTfiltered_signal)*2, 'DisplayName','Filtered')
hold off
grid
xlim([0 5])
xlabel('Frequency (Hz)')
ylabel('Magnitude')
legend('Location','best')
function [FTs1,Fv] = FFT1(s,t)
s = s(:);
t = t(:);
L = numel(t);
Fs = 1/mean(diff(t));
Fn = Fs/2;
NFFT = 2^nextpow2(L);
FTs = fft((s - mean(s)).*hann(L), NFFT)/sum(hann(L));
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
FTs1 = FTs(Iv);
end
.

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