Error in the anonymous function

Sorry for the basic question, but a help is much appreciated.

I'have following code below and I'm trying to select randomly single value for two or more variables from a vector of 1x24. Self is the vector, here the error appears as follwing. I also find the syntax error, however, I can't see in problem from myside.

S_r = length (Self);...

↑

Error: Incorrect use of '=' operator. To assign a value to a variable, use '='. To compare values for equality, use

'=='.

P_k = @(Self, ny)(...
    S_r = length (Self,);...
    R_p  = randperm(S_r);...
    D_i = R_p(1:ny);...
    C_a(D_i)... 
    );

In addition, I also see syntax errors e.g., invalid syntax at '='.A'(' on line 26 might be missing')' line 26 is the first line.

And on the last line it is parse error at ')': usage might invalid syntax error

I can also attached a simple example of the whole secnario below.

 Define A as a 1x24 vector
A = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ...
11, 12, 13, 14, 15, 16, 17, 18, 19, 20, ...
21, 22, 23, 24];

% Define an anonymous function that returns a random subset of n values from A
sample = @(A, n) ( ... % Use @ to define an anonymous function
N = length(A); ... % Get the size of A
P = randperm(N); ... % Generate a random permutation of the indices of A
I = P(1:n); ... % Select the first n indices from the permutation
A(I) ... % Access the corresponding values of A
);

% Define the number of iterations
iterations = 24;

% Loop for each iteration
for i = 1:iterations
% Sample two values from A and assign them to B and C
[B, C] = sample(A, 2);
% Print B and C
fprintf('Iteration %d: B = %d, C = %d\n', i, B, C);
end

Answer 1

[VBBV]

% Define A as a 1x24 vector
AA = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ...
11, 12, 13, 14, 15, 16, 17, 18, 19, 20, ...
21, 22, 23, 24];
n = 2;  % change the value here
N = length(AA); % Get the size of A

% Define the number of iterations
iterations = 24;

% Loop for each iteration
for i = 1:iterations
    

P = randperm(N); ... % Generate a random permutation of the indices of A
I = P(1:n); ... % Select the first n indices from the permutation
AA(I); % Access the corresponding values of A

% Define an anonymous function that returns a random subset of n values from A
sample = @(A, n) [N P I A]; %... % Use @ to define an anonymous function

fprintf('Iteration %d: \n', i)
% Sample two values from A and assign them to B and C
sample(AA(i), n)
% Print B and C

end

Iteration 1: 

ans = 1×28

24 20 12 3 8 13 22 17 5 2 10 14 24 18 11 9 15 23 16 19 7 1 6 4 21 20 12 1

Iteration 2: 

ans = 1×28

24 16 17 10 6 24 20 13 9 1 3 18 21 22 12 4 7 15 2 23 8 11 5 19 14 16 17 2

Iteration 3: 

ans = 1×28

24 8 10 3 6 13 11 17 19 4 15 12 14 22 9 20 18 21 23 16 7 1 5 24 2 8 10 3

Iteration 4: 

ans = 1×28

24 15 14 24 10 19 23 21 17 13 12 18 22 1 5 6 4 9 16 3 20 2 8 7 11 15 14 4

Iteration 5: 

ans = 1×28

24 24 1 23 12 5 8 15 9 17 6 19 21 14 13 16 4 11 2 18 22 3 20 10 7 24 1 5

Iteration 6: 

ans = 1×28

24 12 13 24 1 11 8 22 10 15 6 19 4 7 20 16 5 21 23 14 17 2 9 18 3 12 13 6

Iteration 7: 

ans = 1×28

24 13 1 9 6 18 19 17 23 15 8 7 21 2 11 12 3 14 10 5 20 24 22 16 4 13 1 7

Iteration 8: 

ans = 1×28

24 6 4 14 17 3 10 16 22 20 5 13 12 2 23 18 11 24 8 9 21 7 1 15 19 6 4 8

Iteration 9: 

ans = 1×28

24 6 9 13 23 5 21 1 2 14 15 7 22 12 16 10 24 3 20 19 17 11 18 8 4 6 9 9

Iteration 10: 

ans = 1×28

24 12 19 2 4 6 8 3 16 11 14 18 23 17 10 21 15 5 13 22 24 20 7 9 1 12 19 10

Iteration 11: 

ans = 1×28

24 5 8 7 21 6 2 3 22 4 15 10 13 12 19 9 1 14 23 16 24 20 17 11 18 5 8 11

Iteration 12: 

ans = 1×28

24 12 5 21 6 24 9 7 1 11 19 22 10 2 16 14 3 13 18 15 8 23 4 17 20 12 5 12

Iteration 13: 

ans = 1×28

24 18 16 19 11 3 14 20 24 9 17 22 7 5 8 4 12 15 6 1 10 23 2 21 13 18 16 13

Iteration 14: 

ans = 1×28

24 6 5 11 8 3 22 17 23 24 2 13 14 16 15 9 20 7 19 18 4 10 21 1 12 6 5 14

Iteration 15: 

ans = 1×28

24 23 24 2 1 21 12 13 19 20 14 8 22 18 4 3 6 10 16 9 5 15 11 17 7 23 24 15

Iteration 16: 

ans = 1×28

24 8 18 23 21 1 22 20 3 10 15 11 4 6 5 17 7 13 14 19 12 9 16 2 24 8 18 16

Iteration 17: 

ans = 1×28

24 7 17 2 12 24 23 13 4 3 19 15 21 14 22 16 20 1 5 11 18 6 8 10 9 7 17 17

Iteration 18: 

ans = 1×28

24 18 10 5 24 15 12 19 11 16 22 8 6 14 13 4 7 1 2 21 9 3 23 17 20 18 10 18

Iteration 19: 

ans = 1×28

24 11 5 23 12 15 16 3 7 10 22 9 19 6 20 24 14 13 17 8 18 1 21 4 2 11 5 19

Iteration 20: 

ans = 1×28

24 19 21 14 12 13 20 10 15 24 6 11 1 17 8 2 18 16 4 7 22 23 5 3 9 19 21 20

Iteration 21: 

ans = 1×28

24 12 4 1 19 2 17 10 22 23 11 6 16 5 21 13 9 7 3 18 14 24 8 15 20 12 4 21

Iteration 22: 

ans = 1×28

24 23 11 16 8 19 24 22 2 14 6 10 1 5 9 4 15 17 13 3 20 18 12 21 7 23 11 22

Iteration 23: 

ans = 1×28

24 5 8 19 18 23 24 1 21 3 9 16 7 12 17 15 14 2 20 10 22 13 6 4 11 5 8 23

Iteration 24: 

ans = 1×28

24 10 8 15 17 23 16 20 19 18 7 2 1 3 14 4 11 5 9 12 24 6 21 13 22 10 8 24

[VBBV]

You could try this way. Is this what you mean ?

[VBBV]

' ( ' and ' ) ' are parenthesis used for named function definitions. However, for anonymous function definitons they may not be needed.

[shane watson]

@VBBV, Thanks for your response, a bit late to respond you, however, I'm wondering that why matrix size increased from 1x24? And you also, you didn't assign values to B and C. I already accepted your answer, however, could you please respond to me. thanks in advanced