Trouble using diffuse function
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Jennifer
el 11 de Mzo. de 2024
Comentada: Jennifer
el 11 de Mzo. de 2024
Hello, I'm trying to use the diffuse() function to simulate Lamburtian reflectance off a surface and the help page leaves a bit to be desired. I'm having several errors running the function and was just hoping someone could provide me with an example use of the function so that I can confirm the syntax I'm using is correct.
My end goal is to calculate the reflected light off the surface and compare it to the light that continues past the target and reflects off a second surface. Any help would be greatly appreciated.
0 comentarios
Respuesta aceptada
Florian Bidaud
el 11 de Mzo. de 2024
Editada: Florian Bidaud
el 11 de Mzo. de 2024
The structure is:
R = diffuse(Nx,Ny,Nz,S)
The output R is defined with Lambert's Law by R = cos(psi) where psi is the angle between the surface normal and light source.
If you have a surface on the (x,y) plan, the normal vector is [Nx,Ny,Nz] = [0,0,1].
S = [Theta Phi] is the direction vector of the light source in spherical coordinates (in degrees).
For example
S = [10 45];
R = diffuse(0,0,1,S)
You can also define S in the (x,y,z) coordinates. That would give, to have the same output:
S = [sind(45)*cosd(10) sind(45)*sind(10) cosd(45)];
R = diffuse(0,0,1,S)
Más respuestas (0)
Ver también
Categorías
Más información sobre Lighting, Transparency, and Shading en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!