Converting acceleration data to displacement data using FFT results in Zero-drift

32 visualizaciones (últimos 30 días)
I have a (n x 1) vector containing acceleration data from a sensor and I am trying to obtain the displacement by:
  1. performing an FFT
  2. Convert acceleration to displacement in the frequency domain by dividing by -omega^2
  3. performing an IFFT to get back to the time domain.
The idea is to make a conversion which doesn't result in any Zero-drift, but all my attempts so far result in the oscillation being superimposed on a very low frequency wave (See figure attached), and I can't tell where this low frequency oscillation is coming from. The result should be a near sinusoidal wave centred around zero.
Below is a (slightly modified) snippet from my code. The sensor data (Ch5) is attached as a .mat file.
Tinterval = 0.000625;
Length = length(Ch5);
SamplingFrequency = 1/Tinterval;
Frequency = SamplingFrequency*(0:Length-1)/Length;
Omega = 2*pi*Frequency;
ConversionFactor = -(Omega.^2).';
ConversionFactor(1,:) = 1; %To avoid dividing by zero
% Base Data
RawData = Ch5;
Data = RawData - mean(RawData);
FourierTransform = fft(Data);
Y_accel_base = ifft(FourierTransform).';
dY_base = abs(ifft(FourierTransform./ConversionFactor)).';
  2 comentarios
Mathieu NOE
Mathieu NOE el 27 de Mayo de 2024
hello
doing it by fft/ifft is a requirement or just an idea ?
also notice that the raw data is not zero mean, so you're going to have drift on first integration then a parabolic trend on the 2nd integration
Johann Vormadal
Johann Vormadal el 28 de Mayo de 2024
Hi,
In my code I remove my DC offset before applying the fft.
The requirement is to have zero drift. the fft/ifft seems to be the best way to acheive this (in theory).

Iniciar sesión para comentar.

Respuestas (1)

Mathieu NOE
Mathieu NOE el 27 de Mayo de 2024
FYI, a very simple time domain approach - assuming we don't care about the DC values , only the dynamic portion of the data is of interest
results may be even refined by adding some high pass filtering if you really need it
load('Ch5 data.mat')
dt = 0.000625;
fs = 1/dt; % sampling rate
acc = Ch5;
samples = numel(acc);
t = (0:samples-1)*dt;
% remove DC value
acc = acc - mean(acc);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
velocity = cumtrapz(dt,acc);
velocity = detrend(velocity); % baseline correction
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
disp = cumtrapz(dt,velocity);
disp = detrend(disp); % baseline correction
%
figure(1)
subplot(311),plot(t,acc);
title('accel'); ylabel('m/s²');xlabel('time (s)');
subplot(312),plot(t,velocity);
title('velocity'); ylabel('m/s');xlabel('time (s)');
subplot(313),plot(t,disp);
title('disp'); ylabel('m');xlabel('time (s)');
  5 comentarios
Johann Vormadal
Johann Vormadal el 29 de Mayo de 2024
Thank you for those links!
Those also use the fft method, but their code is slightly different and much more elegant. I will try and emulate them, and see if it solves my problem.

Iniciar sesión para comentar.

Categorías

Más información sobre Antennas, Microphones, and Sonar Transducers en Help Center y File Exchange.

Productos


Versión

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by