Name a dataset that will be used in Simulink

How do I name a dataset. My dataset is available in Simulink; however, it is identified as unnamed. I want to use multiple datasets so I need to be able to identify each of them separately.

clc

% Parameters

f0 = 60; % Fundamental frequency in Hz

sampling_rate = 120000; % Sampling rate in Hz

stopTime = 0.1; % Duration of the signal in seconds

t = 0:1/sampling_rate:stopTime; % Time vector

% Harmonic amplitudes (example values)

IA = [771.32, 0.24,1.36, 0.96, 6.64, 0.16, 2.36, 0, 0.48,...

0.16, 1.84, 0.08, 0.56, 0.08, 0.32, 0.08, 0.24,...

0.08, 0.08, 0.08, 0.08, 0, 0.48, 0, 0.16, 0.08, 0.08, 0, 0.08, 0, 0, 0, 0,...

0.08, 0.24, 0.16, 0.32, 0.08, 0.08, 0.08, 0.32,...

0.08, 0.24, 0.16, 0.24, 0.08, 0.8, 0.16, 0.48,...

0.16, 0.16, 0.08, 0.72, 0.24, 0.72, 0.16, 0.24,...

0.08, 0.16, 0.08, 0.56, 0.08, 0.32]'; % Amplitudes for the 1st, 2nd, and 3rd harmonics

IB = [773.44, 0.4, 0.72, 0.88, 6.16, 0.4, 2.84, 0.08, 0.4, 0.08,...

1.76, 0.08, 0.96, 0.08, 0.16, 0, 0.4, 0.08, ...

0.24, 0.08, 0, 0, 0.4, 0, 0.24, 0,...

0.08, 0, 0.08, 0, 0.08, 0, 0.16, 0.08,...

0.16, 0.08, 0.32, 0.08, 0.08, 0, 0.24, 0.08,...

0.4, 0.08, 0.08, 0.08, 0.8, 0.08, 0.72, 0.16,...

0.08, 0.32, 0.48, 0, 0.08, 0.08, 0.24, 0.32,...

0.24, 0.24, 0.72, 0.24, 0.08];

IC = [775.76, 0.24, 0.56, 0.72, 6.48, 0.24, 2.44, 0.08, 0.08, 0.08, ...

2.12, 0, 0.72, 0.08, 0.16, 0.08,...

0.32, 0, 0.08, 0, 0, 0, 0.56, 0, 0.08, 0, 0.08, 0, ...

0, 0, 0.08, 0, 0, 0, 0.24, 0, 0.24, 0, 0, 0.08, 0.24, 0, 0.32, 0,...

0.08, 0.08, 0.8, 0.08, 0.56, 0.08, 0.32, 0.08,...

0.64, 0.32, 0.56, 0.08, 0.24, 0.32, 0.24, 0.32, 0.72, 0.16, 0.24];

%% Generate the current

currentIA = zeros(size(t));

currentIB = zeros(size(t));

currentIC = zeros(size(t));

for n = 1:length(IA)

amplitudeIA = IA(n);

currentIA = currentIA + amplitudeIA * cos(2 * pi * n * f0 * t);

amplitudeIB = IB(n);

currentIB = currentIB + amplitudeIB * cos(2 * pi * n * f0 * t + 2*pi/3);

amplitudeIC = IC(n);

currentIC = currentIC + amplitudeIC * cos(2 * pi * n * f0 * t - 2*pi/3);

end

currents = timeseries([currentIA; currentIB; currentIC]', t);

dataset = Simulink.SimulationData.Dataset(currents); %How do I give the dataset a name?

save currentsWith63Harmonics.mat dataset

%% Plot the signal

figure(1);

plot(t, currentIA);

hold on

plot(t, currentIB);

plot(t, currentIC);

title('Three-Phase currents with 63 harmonics');

xlabel('Time (s)');

ylabel('A');

grid on;

figure(2);

ee_calculateThdPercent(1:1:63,IA')

bar(1:1:63,IA')

clear IA IB IC f0 duration amplitudeIA amplitudeIB amplitudeIC

clear n t signal

Answer 1

[Paul]

Hi David,

The 'unnamed' in that block is the name of the signal, not the dataset.

f0 = 60; % Fundamental frequency in Hz
sampling_rate = 120000; % Sampling rate in Hz
stopTime = 0.1; % Duration of the signal in seconds
t = 0:1/sampling_rate:stopTime; % Time vector
% Harmonic amplitudes (example values)
IA = [771.32, 0.24,1.36, 0.96, 6.64, 0.16, 2.36, 0, 0.48,...
0.16, 1.84, 0.08, 0.56, 0.08, 0.32, 0.08, 0.24,...
0.08, 0.08, 0.08, 0.08, 0, 0.48, 0, 0.16, 0.08, 0.08, 0, 0.08, 0, 0, 0, 0,...
0.08, 0.24, 0.16, 0.32, 0.08, 0.08, 0.08, 0.32,...
0.08, 0.24, 0.16, 0.24, 0.08, 0.8, 0.16, 0.48,...
0.16, 0.16, 0.08, 0.72, 0.24, 0.72, 0.16, 0.24,...
0.08, 0.16, 0.08, 0.56, 0.08, 0.32]'; % Amplitudes for the 1st, 2nd, and 3rd harmonics
IB = [773.44, 0.4, 0.72, 0.88, 6.16, 0.4, 2.84, 0.08, 0.4, 0.08,...
1.76, 0.08, 0.96, 0.08, 0.16, 0, 0.4, 0.08, ...
0.24, 0.08, 0, 0, 0.4, 0, 0.24, 0,...
0.08, 0, 0.08, 0, 0.08, 0, 0.16, 0.08,...
0.16, 0.08, 0.32, 0.08, 0.08, 0, 0.24, 0.08,...
0.4, 0.08, 0.08, 0.08, 0.8, 0.08, 0.72, 0.16,...
0.08, 0.32, 0.48, 0, 0.08, 0.08, 0.24, 0.32,...
0.24, 0.24, 0.72, 0.24, 0.08];
IC = [775.76, 0.24, 0.56, 0.72, 6.48, 0.24, 2.44, 0.08, 0.08, 0.08, ...
2.12, 0, 0.72, 0.08, 0.16, 0.08,...
0.32, 0, 0.08, 0, 0, 0, 0.56, 0, 0.08, 0, 0.08, 0, ...
0, 0, 0.08, 0, 0, 0, 0.24, 0, 0.24, 0, 0, 0.08, 0.24, 0, 0.32, 0,...
0.08, 0.08, 0.8, 0.08, 0.56, 0.08, 0.32, 0.08,...
0.64, 0.32, 0.56, 0.08, 0.24, 0.32, 0.24, 0.32, 0.72, 0.16, 0.24];
%% Generate the current
currentIA = zeros(size(t));
currentIB = zeros(size(t));
currentIC = zeros(size(t));
for n = 1:length(IA)
    amplitudeIA = IA(n);
    currentIA = currentIA + amplitudeIA * cos(2 * pi * n * f0 * t);
    amplitudeIB = IB(n);
    currentIB = currentIB + amplitudeIB * cos(2 * pi * n * f0 * t + 2*pi/3);
    amplitudeIC = IC(n);
    currentIC = currentIC + amplitudeIC * cos(2 * pi * n * f0 * t - 2*pi/3);
end
currents = timeseries([currentIA; currentIB; currentIC]', t); 
dataset = Simulink.SimulationData.Dataset(currents); %How do I give the dataset a name?

Looking at dataset

dataset

dataset = 
Simulink.SimulationData.Dataset 'currents' with 1 element

                         Name     BlockPath 
                         _______  _________ 
    1  [1x1 Signal]      unnamed  ''       

  - Use braces { } to access, modify, or add elements using index.

we see that it does have a name 'currents', which I guess it was given automatically based in the variable name in its constructor. The dataset name can be changed if you want. But the issue you're seeing is that the signal inside the dataset is unnamed. You can change that when currents is created

currents = timeseries([currentIA; currentIB; currentIC]', t,'Name','allcurrents');
dataset = Simulink.SimulationData.Dataset(currents)

dataset = 
Simulink.SimulationData.Dataset 'currents' with 1 element

                         Name         BlockPath 
                         ___________  _________ 
    1  [1x1 Signal]      allcurrents  ''       

  - Use braces { } to access, modify, or add elements using index.

Now the outuput from the Signal Editor block will be 'allcurrents'.

You can also operate on dataset directly to assign a name to that signal.

dataset{1}.Name = 'thecurrents'

dataset = 
Simulink.SimulationData.Dataset 'currents' with 1 element

                         Name         BlockPath 
                         ___________  _________ 
    1  [1x1 Signal]      thecurrents  ''       

  - Use braces { } to access, modify, or add elements using index.

[David Cole]

Works great! Thanks.