How to Integration this function?

Is there anyway we can integrate exp(z*(z+1)/(z-1)) with respect to z?

3 comentarios

Sam Chak
Sam Chak el 13 de Feb. de 2026 a las 12:13
The function has a discontinuity at . From the plots below, the integral cannot converge in the interval
syms z
f = exp(z*(z + 1)/(z - 1));
subplot(121)
fplot(f, [-7, 1])
xlabel('z')
title('f(z < 1)')
ylim([0, 1.2])
subplot(122)
fplot(f, [1, 3])
xlabel('z')
title('f(z > 1)')
ylim([0, 5000])
simran
simran el 13 de Feb. de 2026 a las 12:19
Yes, I'm sorry I didn't mention earlier, I'm working in unit disk only, so |z|<1.
Torsten
Torsten el 13 de Feb. de 2026 a las 12:49
Editada: Torsten el 13 de Feb. de 2026 a las 12:49
If f is holomorphic in the disc |z|<=r<1, integral_{ |z|<=r } f(z) dz = pi*r^2*f(0). Then take the limit r -> 1-.

Respuestas (0)

La pregunta está cerrada.

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R2024b

Preguntada:

el 13 de Feb. de 2026 a las 11:09

Cerrada:

el 13 de Feb. de 2026 a las 15:38

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