Need to remove '~' in column 5 of text file

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jgillis16
jgillis16 el 30 de Jul. de 2015
Comentada: jgillis16 el 30 de Jul. de 2015
content = fileread('mwithin21rm.txt');
linestocopy = regexp(content, '^([^|]*\|){5}~\|.*$', 'match', 'dotexceptnewline', 'lineanchors');
newfile = fopen('m21rmmorphU.txt', 'wt');
fprintf(newfile, strjoin(linestocopy, '\n'));
fclose(newfile);
I need to remove the '~' in column 4 from each line of the text file. The code above moves those lines into a new text file, but I need to eliminate those lines instead. I have attached the file, mwithin21rm.txt.
  2 comentarios
Cedric
Cedric el 30 de Jul. de 2015
Editada: Cedric el 30 de Jul. de 2015
There is no '~' in column 4; seeing your pattern, it is column 5.
jgillis16
jgillis16 el 30 de Jul. de 2015
Apologies for the mistake. Thanks for catching it! Do you have any idea on how to proceed?

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Respuesta aceptada

Cedric
Cedric el 30 de Jul. de 2015
Editada: Cedric el 30 de Jul. de 2015
UPDATE 5:04pm
% - Read original.
content = fileread( 'mwithin21rm.txt' ) ;
% - Match and eliminate lines without pattern matching.
sepId = reshape( strfind( content, '|' ), 18, [] ) ;
match = content(sepId(4,:)+1) == '~' ;
lines = strsplit( content, '\n' ) ;
lines(match) = [] ;
% - Export updated content.
fId = fopen( 'm21rmmorphU.txt', 'w' ) ;
fprintf( fId, strjoin( lines, '\n' )) ;
fclose( fId ) ;
FORMER
If I understand well (in particular about col. 5), you want something like this:
% - Read original.
content = fileread( 'mwithin21rm.txt' ) ;
% - Replacement which avoids pattern matching.
sepId = reshape( strfind( content, '|' ), 18, [] ) ;
match = content(sepId(4,:)+1) == '~' ;
content(sepId(4,match)+1) = '' ;
% - Export updated content.
fId = fopen( 'm21rmmorphU.txt', 'w' ) ;
fwrite( fId, content ) ;
fclose( fId ) ;
PS: I love regular expressions ;-) but this seems to be a case where we can avoid their complexity.
  3 comentarios
Cedric
Cedric el 30 de Jul. de 2015
Ok, I am updating the answer.
jgillis16
jgillis16 el 30 de Jul. de 2015
Thank you!

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