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How to have 2 legend entries for 1 set of data using bar plot?

5 visualizaciones (últimos 30 días)
I have a bar plot with 1 set of data and I colorized the bars to highlight some differences after a threshold. Now I would like to have 2 entries in the legend but I cant figure out how to do that.
Matlab recognizes there is only 1 set of data and adds only 1 legend entry. Smart Matlab...
Is there a way to disable this to? Or another suggestions?
% test data
data = 1:10;
% bar plot
bar_h = bar(data);
% colorize bars
bar_child = get(bar_h,'Children');
% create custom color map
mycolor=[0 0 1;1 0 0]; %set colors
colormap(mycolor)
blue = 1*(data<8);
red = 2*(data>=8);
index = blue + red;
% apply colors
set(bar_child,'CData',index);
% legend
legend('blue','red')
edit: added a picture of what I mean

Respuesta aceptada

Star Strider
Star Strider el 25 de Ag. de 2015
Editada: Star Strider el 25 de Ag. de 2015
One possibility:
% test data
data = 1:10;
data1 = data(data<8);
data2 = data(data>=8);
% bar plot
bar_h1 = bar([1:7], data1,'b');
hold on
bar_h2 = bar([8:10], data2,'r');
hold off
set(gca, 'XTick',[1:10])
legend('blue','red', 'Location','NW')
I’m using R2015a, so can’t use your ‘bar_child’ and related data and calls. The set call for the 'XTick' values was necessary because without it the ticks for [8:10] don’t plot for some reason, even when specifically stating them in the bar call. Weird.
EDIT — Added 'Location' to legend call.
  2 comentarios
Norris
Norris el 25 de Ag. de 2015
Editada: Norris el 25 de Ag. de 2015
Works like a charm!! Thanks so much. I did try to split the data into 2 sets of bars but didnt get it to work earlier.
Cheers.
Star Strider
Star Strider el 25 de Ag. de 2015
My pleasure.
Plotting two sets of bars requires the hold function, to be certain the second set of bars does not overplot the first set. I too had problems getting it to work as I wanted it to, thus the set call. (There are also version differences between R2014a and earlier, and R2014b and later, so I did my best to provide a ‘universal’ approach.)

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