Dynamically arrange the matrix in each for loop

I have two matrix a = [3 5 6 7] and b = [2 4 6 1; 5 7 8 9]. I need to dynamic arrange the matrix b when the position of a is changing.

For example,

First loop, a = [3 5 6 7]

    b = [2 4 6 1
         5 7 8 9]

But at the second loop, the position for b is changed a = [7 3 5 6]

    b = [1 2 4 6
         9 5 7 8]

and so on for the subsequent loop. Is this possible to happen? Thank you.

Answer 1

[Eric Pahlke]

Definitely possible.

a = [3 5 6 7]; 
b = [2 4 6 1; 5 7 8 9];

for ii = 1:4
    % do_stuff(a,b);

      disp('iteration:')
      disp(ii);
      a
      b

      a = [a(end) a(1:end-1)];
      b = [b(:,end) b(:,1:end-1)];

end

[Chin]

How about each time the position for the b is random? Which means the

iteration 1 b = [3 5 6 7]

iteration 2 b = [5 3 7 6]

iteration 3 b = [7 3 5 6]

iteration 3 b = [6 5 7 3]

and so on. Thank you.

[Andrei Bobrov]

c = cell(1,4)

for j1 = 1:4

c{j1} =circshift([a;b],[0 j1]);

end

[Chin]

The problem is when a = [6 5 3 7]

i will get the result b = [6 4 2 1; 8 7 5 9]. Is that possible need to use indexing?

[Andrei Bobrov]

x = a(randperm(4));

[loc,loc] = ismember(x,a);

b1 = b(:,loc)