How to bin for scatter plot from two data series?

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trailokya
trailokya el 15 de Sept. de 2015
Comentada: Star Strider el 16 de Sept. de 2015
Sir i have two data series say
a b
25.36737061 -27.47956892
20.54391479 -23.68162398
16.76391602 -16.65254461
9.47177124 -19.20600915
16.25158691 -18.56570783
4.462646484 -14.39363913
7.785919189 -14.98048449
12.27481079 -18.49125231
4.851806641 -19.91135093
2.111236572 -5.049334665
-1.457702637 -6.51219601
1.85055542 -1.299793246
and i want to plot for a=0-5,6-10,11-15,16-20 with the corresponding average and standard deviation of b. Please help me with a easy way since the series are very large?

Respuesta aceptada

Star Strider
Star Strider el 15 de Sept. de 2015
Editada: Walter Roberson el 15 de Sept. de 2015
This seems to work:
m = [25.36737061 -27.47956892
20.54391479 -23.68162398
16.76391602 -16.65254461
9.47177124 -19.20600915
16.25158691 -18.56570783
4.462646484 -14.39363913
7.785919189 -14.98048449
12.27481079 -18.49125231
4.851806641 -19.91135093
2.111236572 -5.049334665
-1.457702637 -6.51219601
1.85055542 -1.299793246];
binedge = 0:5:20; % Define Bin Edges
[acount, idx] = histc(m(:,1), binedge); % Bin ‘a’, Return Index Vector
meanb = accumarray(idx+1, m(idx+1,2), [], @mean); % Get Mean Of Corresponding ‘b’
figure(1)
bar(binedge, acount, 'histc')
grid
One of the bin edge values is zero, and that doesn’t work as an index for accumarray, so I added 1 to the index values. That doesn’t affect the calculation.
  4 comentarios
Star Strider
Star Strider el 16 de Sept. de 2015
I didn’t specifically test the code for the standard deviation, but it should work as you wrote it, providing there are no NaN values in your data.
Star Strider
Star Strider el 16 de Sept. de 2015
If my Answer solved your problem, please Accept it.

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