Info

La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.

How do I deal with this function handel error?

1 visualización (últimos 30 días)
Ruten9
Ruten9 el 25 de Oct. de 2015
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
my height file:
function h = height(t)
h = @(t) ((-9.8).*(2.^(-1))).*(t.^2) + 125.*t + 500;
h(h<0) = 0;
if h(t) <0
then h=0
end
end
My main file:
clear all; clc;
t = 0:.01:35;
h = height(t)
%Part C (maxima)
[xpsudeomax,ymax] = max(h(t));
xrealmax = t(ymax);
maxfunction = [xrealmax,ymax];
%fminbnd function
[xmax2,ymaxpsudeo]= fminbnd(@(t) (-1.*h(t)),0,30);
yrealmax = -1.*ymaxpsudeo;
format long g
fminbndmax = [xmax2,yrealmax] ;
%Part D
[xzero,ypsuedozero]= fzero(@(t) h(t),20);
yrealzero = round(ypsuedozero);
ZERO = [xzero,yrealzero];
%Part B (height vs time)
figure;
plot(t,h(t),'blue',xmax2,yrealmax,'go','LineWidth',2);
hold on;
plot(xzero,yrealzero,'r.','MarkerSize',20);
title('Rocket Trajectory');
ylabel('altitude [m]');
xlabel('time [sec]');
axis([0 35 0 1500]);
legend('height','max','ground','location','ne')
I keep getting the
"Undefined operator '<' for input arguments of type 'function_handle'.
Error in height (line 7)
h(h<0) = 0;"
How would I resolve this? I got everything on my graph right, but I can't get the flat,horizontal line to appear at the very end.
  3 comentarios
Ruten9
Ruten9 el 25 de Oct. de 2015
How would I go about that for this problem? I'm very lost.

Respuestas (1)

Gareth Thomas
Gareth Thomas el 25 de Oct. de 2015
Try to remove: h(h<0) = 0;
From your height function. This will help you.
  2 comentarios
Ruten9
Ruten9 el 25 de Oct. de 2015
My hw says that it should be there. I'm not sure why though.
Walter Roberson
Walter Roberson el 26 de Oct. de 2015
Then either your "hw" is wrong or you have misinterpreted your "hw" or you have implemented in a way that you are not intended to use.

La pregunta está cerrada.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by