xpos(i) in Polygonal domain

3 visualizaciones (últimos 30 días)
Hamid
Hamid el 3 de En. de 2012
Hi, I need to define random point positions within a polygonal domain. So far, I am only able to realize the random positions of my points in the quadratic plot window with
for i=1:6000 xpos(i)=100*rand; ypos(i)=100*rand; end
So I want to arrange these points arbitrary within a polygon. I would really appreciate any help.

Respuesta aceptada

Andrew Newell
Andrew Newell el 3 de En. de 2012
You could generate random points in a rectangle enclosing the polygon and then choose the points that lie inside using inpolygon. The documentation for this function even provides an example that is similar to what you want to do.

Más respuestas (5)

Jose Jeremias Caballero
Jose Jeremias Caballero el 3 de En. de 2012
xpos=100*rand(1,5);
ypos=100*rand(1,5);
plot([xpos xpos(1)],[ypos ypos(1)])
for i=1:length(xpos)
text(xpos(i),ypos(i),[num2str(xpos(i)),',',num2str(ypos(i))])
end

Hamid
Hamid el 3 de En. de 2012
Dear Jose,
I am not really sure, whether this is the solution for my problem. Probably I didn't phrase it well. I need to define 6000 points within a ploygon domain! The polygon should be fixed and predefined with 8 edges.

Jose Jeremias Caballero
Jose Jeremias Caballero el 3 de En. de 2012
%random_polygon
xpos=100*rand(1,6000);
ypos=100*rand(1,6000);
xmin=min(xpos)-2; ymin=min(ypos)-2;
xmax=max(xpos)+2; ymax=max(ypos)+2;
X=[xmin xmin xmax xmax xmin];
Y=[ymin ymax ymax ymin ymin];
plot(X,Y)
for i=1:length(xpos)
text(xpos(i),ypos(i),'*')
end
  1 comentario
Hamid
Hamid el 3 de En. de 2012
Dear Jose, First let me thank you for your efforts to help me.
This answer gives me a random polygon. I already have a ploygon defined as
X=[10 30 41 50 65 70 40 15 5 10];
Y=[37 35 15 10 15 37 58 60 50 37];
plot(X,Y)
But I want to define my random points so that they are inside this polygon.

Iniciar sesión para comentar.


Jose Jeremias Caballero
Jose Jeremias Caballero el 3 de En. de 2012
a=100;
xpos=a*rand(1,6000);
ypos=a*rand(1,6000);
X5 = [10 30 41 50 65 70 40 15 5 10];
Y5 = [37 35 15 10 15 37 58 60 50 37];
figure(gcf)
T=xpos<max(X5) & min(X5)<=xpos;
M=xpos(T);
N=ypos(T);
n=length(M);
for i=1:n
for j=1:n-i
if M(j)>=M(j+1)
aux=M(j);
auy=N(j);
M(j)=M(j+1);
N(j)=N(j+1);
M(j+1)=aux;
N(j+1)=auy;
end
end
end
U=N<max(Y5) & min(Y5)<N;
M1=M(U);
N1=N(U);
for i=1:length(X5)
normas(i)=norm([X5(i) Y5(i)]);
end
k=1;
for i=1:length(M1)
if (min(normas)<norm([M1(i) N1(i)]) && norm([M1(i) N1(i)])<max(normas))
M2(k)=M1(i);
N2(k)=N1(i);
k=k+1;
end
end
plot(X5,Y5)
for i=1:length(M2)
text(M2(i),N2(i),'*')
end
grid
axis('image')
axis([min(X5)-20 max(X5)+20 min(Y5)-20 max(Y5)+20])

Jose Jeremias Caballero
Jose Jeremias Caballero el 3 de En. de 2012
%thaks Andrew Newell.
a=100;
xpos=a*rand(1,6000);
ypos=a*rand(1,6000);
X5 = [10 30 41 50 65 70 40 15 5 10];
Y5 = [37 35 15 10 15 37 58 60 50 37];
interno = inpolygon(xpos,ypos,X5,Y5);
plot(X5,Y5,xpos(interno),ypos(interno),'.r')

Categorías

Más información sobre Elementary Polygons en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by