Vectorization of a for loop

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jpedro
jpedro el 9 de Nov. de 2015
Editada: Guillaume el 10 de Nov. de 2015
Hello,
I am trying to eliminate the loop and vectorise this piece of code. Any ideas?
for k = 1:(length(P)-2)
if ((P(k+1)-P(k)>0)&&(P(k+2)-P(k+1)<0));
B(k+1) = 1;
end
end
Thanks

Respuestas (2)

Peter O
Peter O el 9 de Nov. de 2015
v = 1:length(P)-2;
ix = find( ((P(v+1) - P(v)) > 0) & ((P(v+2) - P(v+1)) < 0) ) + 1;
B2(ix) = 1;
  1 comentario
jpedro
jpedro el 10 de Nov. de 2015
Hello Peter,
Thanks for your answer, but that code doesn't give the same results as the for above

Iniciar sesión para comentar.


Guillaume
Guillaume el 10 de Nov. de 2015
Editada: Guillaume el 10 de Nov. de 2015
Well, P(k+1)-P(k) can be obtained in a vectorised way with the diff function, so, assuming that by default B(k) is zero:
B = diff(P(1:end-1)) > 0 & diff(P(2:end)) < 0 %no need to preinitialise B
If by default, B(k) is something else:
B(diff(P(1:end-1)) > 0 & diff(P(2:end)) < 0) = 1; %B must be preinitialised

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