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Search rows of a matrix on another

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Matlab User
Matlab User el 16 de Nov. de 2015
Comentada: Matlab User el 16 de Nov. de 2015
I have two matricies. The first, A, is large (1968x100 double) and the second, T, is smaller (1968x1). In matrix A, each row contains unique elements corresponding to the smaller matrix. For example, A(1,:) = 6 2 3 53..... (up until 100 columns). What I need to do is search in T for the corresponding ROWS and extract their numeric value. So for this example, I need to search in T for the 6th, 2nd, 3rd, 53rd rows and extract their values.
I hope this is clear !!! Any help is much appreciated.
  2 comentarios
Jan
Jan el 16 de Nov. de 2015
Editada: Jan el 16 de Nov. de 2015
A small example with [3 x 4] matrices might explain the problem uniquely.
Do you really want to search the "corresponding rows in T", when T has one row only? Do you mean searching the rows in A instead?
Matlab User
Matlab User el 16 de Nov. de 2015
For each row in A there are 100 elements. T has 1968 rows and 1 column. So, say for example A=[2 3 5;1 2 4;7 8 10], and T=[200;500;750,204,567..... up to 1968 rows], for A(1,:) I want to report the value of the 2nd, 3rd and 5th rows in T, i.e. 500,750 and 567. I hope this is clearer.

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Guillaume
Guillaume el 16 de Nov. de 2015
Editada: Guillaume el 16 de Nov. de 2015
There is no search involved. It's simple matrix indexing:
A = [2 3 5;
1 2 4;
7 8 10];
T = [200; 500; 750; 204; 567; 123; 456; 789; 987; 654; 321];
newA = A; newA(A == 0) = 1; %to cope with zeros
values = T(newA); %that's it!
values(A == 0) = 0 %assuming that you want 0 for A == 0
Note that the shape of T is irrelevant as long as A is a matrix. T can be a column or row vector (or even a matrix).
edited to cope with 0s in A
  3 comentarios
Guillaume
Guillaume el 16 de Nov. de 2015
Editada: Guillaume el 16 de Nov. de 2015
The zeros are indeed a problem. What is supposed to be returned for the zeros?
I've edited my answer to output 0 for these.
Matlab User
Matlab User el 16 de Nov. de 2015
Thankyou that is just what I needed!

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