how to count non breaking ones from matrix?

hello sir/mam,i have a problem in counting non-breaking ones from this given matrix. can you suggest any algo or command to count that. result which i want is (2 2 5 4 2 4 4 2 2 2 2 2 2 2 2 2 3 4 2 4).

Answer 1

[Thorsten]

For a single column, use

diffcol = diff([0; col; 0]);
n = max(find(diffcol==-1)-find(diffcol==1));

Just loop over each column

 for i = 1:size(A,2);
    diffcol = [0; A(:,i); 0];
    n(i) = max(find(diffcol==-1)-find(diffcol==1));
 end

Answer 2

[Andrei Bobrov]

t = [true(1,2);diff(A)~=0];
[m,n]=size(A);
[~,jj] = ndgrid(1:m,1:n);
ii = A.*cumsum(t.*A);
b = accumarray([ii(:)+1,jj(:)],1);
out = max(b(2:end,:));