Simple for loop index

3 visualizaciones (últimos 30 días)
Dirk
Dirk el 10 de Dic. de 2015
Comentada: Torsten el 11 de Dic. de 2015
Hi,
Here is a simple piece of code to find the location of elements n within the vector A
A=[2,4,6,7,9];
for n=[4,9];
x=find(n==A);
end
However x only gives me the last location, i.e. 5, whereas I want the whole list of locations, i.e. [2,9] Thanks

Respuesta aceptada

Torsten
Torsten el 10 de Dic. de 2015
A=[2,4,6,7,9];
index=1;
for n=[4,9]
x(index)=find(n==A);
index=index+1;
end
Best wishes
Torsten.
  3 comentarios
Dirk
Dirk el 10 de Dic. de 2015
Why does this not work with when a decimal is present (for example in A)?
A=[2,4.4,6,7,9];
index=1;
for n=[4,9]
x(index)=find(n==A);
index=index+1;
y=A(x);
end
Torsten
Torsten el 11 de Dic. de 2015
A=[2,4.4,6,7,9];
index=1;
for n=[4,9]
k=find(n==A);
x{index}=k;
y{index}=A(k);
index=index+1;
end
Best wishes
Torsten.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by