Converting Cell Array Output to Logical Matrix

I have an array output consisting of the following characters: "A1a", "A1b", "A2a", "A2b" for e.g.:

    'A1a'    'A2a'
    'A1a'    'A2b'
    'A1b'    'A2a'
    'A1b'    'A2b'

How do I convert it to a logical matrix such that, if the output contains the character "A1a", under the column "A1a", the value will be true" i.e. "1" ?

 %Output
Row  A1a  A1b  A2a  A2b  
1  1  0  1  0  
2  1  0  0  1  
3  0  1  1  0  
4  0  1  0  1

Answer 1

[Star Strider]

This works:

C = {'A1a'    'A2a'
    'A1a'    'A2b'
    'A1b'    'A2a'
    'A1b'    'A2b'};

Cu = unique(C,'stable');
for k1 = 1:length(Cu)
    L{k1} = cellfun(@(x) strcmpi(x,Cu(k1)), C);
    N(:,:,k1) = L{k1};
end
T = squeeze(sum(N,2));
fprintf(1,'\n\tRow\t%3s\t%3s\t%3s\t%3s\n', Cu{:})
fprintf(1, '\t%2.0f\t%2.0f\t%2.0f\t%2.0f\t%2.0f\n', [[1:4]' T]')

  Row  A1a  A1b  A2a  A2b
   1   1   0   1   0
   2   1   0   0   1
   3   0   1   1   0
   4   0   1   0   1

[eugene479]

Thank you so much! It works great!

[Star Strider]

My pleasure!

Answer 2

[Harsheel]

out = cellfun(@(x)(strcmp(x,'A1a')), A); % A is the input cell array

cellfun