How do I convert a cell array to matrix whose dimensions are not equal?

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mydata =
[195x1 double] [124x1 double] [1826x1 double] [2x1826 double] [195x124x1826 single]
Geoff Hayes
Geoff Hayes on 11 Feb 2016
Manoj - how should all of this data, from your cell array, be packaged into the matrix? What should the dimensions be for the matrix?

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Accepted Answer

Walter Roberson
Walter Roberson on 11 Feb 2016
%using variable names from your posting, structure as in capture.JPG
md1 = mydata{1};
md2 = mydata{2};
md3 = mydata{3};
md4 = mydata{4};
md5 = mydata{5};
[X, Y, Z] = ndgrid(md1, md2, md3);
pointsize = 20;
scatter3(X(:), Y(:), Z(:), pointsize, md5(:));
%using variable names from data file.JPG
%the data is a mix of int16 and int32 and we need to make it all the same datatype to
%make it into a numeric matrix without risk that the wrong datatype would be used
temp = cellfun(@(M) int32(M.'), permute(B,[1 3 2]), 'Uniform', 0);
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
The result of this, B30, would be a 30 x 10666 numeric array, in which each row is formed by concatenating together the 2446 x 1, 2532 x 1, 2651 x 1, 3037 x 1 as one piece and making that a row.
Walter Roberson
Walter Roberson on 15 Feb 2016
You have changed the size of your data in mydata. Please show the current summary of mydata and also of B.
The line
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 'Uniform', 0) );
should be
B30 = cell2mat( arrayfun(@(R) horzcat(temp{R,:}), 1:size(temp,1), 'Uniform', 0) );

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