Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 - (cos(x)))/((2* ((x^3)))* sin(x)).
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Shivangi Chauhan
el 11 de Feb. de 2016
Comentada: Torsten
el 11 de Feb. de 2016
Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 - (cos(x)))/((2* ((x^3)))* sin(x)). Using matlab it is 'inf' and using L hospital rule by hand calculation, it is (-1/48). Which one is correct?
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Torsten
el 11 de Feb. de 2016
Plot the function and you'll see that MATLAB's answer is correct.
The function behaves like 1/x^2 near x=0.
Best wishes
Torsten.
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Torsten
el 11 de Feb. de 2016
Which value are you talking about ?
(1-cos(x))/(2*x^3*sin(x)) ~ (1-(1-x^2/2))/(2*x^3*x) = 1/(4*x^2)
near x=0.
We have to see your calculations to point out the error you made.
Best wishes
Torsten.
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