Need Help with Newton's Method for the Following code; keep getting errors
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
clc;
close all;
clear all;
x = 1;
y = 2;
for i = 1:10
f(x) = (-x(i).^2) - (2*y(i)) + 2;
f(y) = (-x(i)) - (4*y(i).^2) + 4;
A(1,1) = 2*x(i);
A(1,2) = 2;
A(2,1) = 1;
A(2,2) = 8*y(i);
Z_new = f'\A + f; %f' denotes a column
x(i) = Z_new(1,1);
y(i) = Z_new(1,2);
end
end
1 comentario
KSSV
el 12 de Feb. de 2016
what is that code? It will not work. x and y are scalars, you are expecting it to be vector inside the loop. You have to read basics of matlab and the problem you are solving.
Respuestas (1)
Marc
el 12 de Feb. de 2016
You may want to look into the following in the documentation:
- @ or annonymous functions
- preallocation
Cleve Moler's recent blog on Newton's method gives a good example of setting up an anonymous function, its derivative and has a simple implementation of newton's method already there.
0 comentarios
Ver también
Categorías
Más información sobre Linear Algebra en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!