Help with Basic Matrix Exercise

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Nicholas Menghi
Nicholas Menghi el 26 de Feb. de 2016
Editada: Nicholas Menghi el 26 de Feb. de 2016
Hi :) I'm learning Matlab by myself with some tutorial that i found online. I know, I'm a newbie but i can't solve this exercise. Could someone help me? Should be very easy cause i found this in a starter course.
Create a 6(rows)x4(columns) matrix filled with random integer values between 1 and 20; Create a zeroes matrix of the same dimensions; Replace each zero with a random number from the other matrix; Display each value in the new mixed matrix
Thank you :)

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Andreas Goser
Andreas Goser el 26 de Feb. de 2016
To get you started, check
doc rand
doc zeros
Probably this is the easy part. If you get to "Replace each zero with a random number from the other matrix;", you may want to share all the code you have to that time in a new question here with your specific struggle (if any).
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Stephen23
Stephen23 el 26 de Feb. de 2016
Editada: Stephen23 el 26 de Feb. de 2016
"But Random number are not integer": Here are three very easy ways you can locate the correct way to generate random integers:
  • use any internet search engine.
  • open the rand page, and browse the Contents on the left-hand-side.
  • open the rand page and click on the links at the very bottom of the page (to related functions).
If you had done any of these things you would immediately find out that there is a function for generating random integers, and rand is not it.
The indexing problem you would also solve in 0.5 seconds using any internet search engine. But here it is, just in case you don't have that much time:
mat2(row,col) % how to index rows and columns
Nicholas Menghi
Nicholas Menghi el 26 de Feb. de 2016
Editada: Nicholas Menghi el 26 de Feb. de 2016
Ok, now I'm stuck here
mat1 = randi(20,6,4)
mat2 = zeros(6,4)
for i= [(1:6),(1:1)]
for k = [(1:1)]:[(1:4)]
mat2(i) = mat1(i)
mat2(k) = mat1(k)
end
end
disp(mat1)
disp(mat2)
I don't know, it changes again only the first column... 0.5... secs now I am feeling a little wretched.

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