How to set up a forloop for calculations between different cells in a cell array?

I'm trying to make a forloop where the first looped variable j stays the same for all 1 through 10 iterations of i before it moves on to the next number (2) and then does all 1:10 iterations of i again and so on until the squared difference has been taken from all combinations of cells within cell1. This is what I've been trying but I'm getting a lot of empty cells [] and incorrect values. What is a better way to implement this?

B = repmat(1:10,1,10);
J = repelem([1 2 3 4 5 6 7 8 9 10], 10);
cell1=cell1={2,1,10,4,1,5,12,2,1,4}
for i = B
  for j = J
    test{i*j} = (cell1{j} - cell1{i}).^2; 
  end
end

Answer 1

[Stephen23]

"What is a better way to implement this?" You don't tell us what "this" is. If you are trying to calculate the squared difference of two vectors, then your method is very complicated, slow, and buggy. You could simply use bsxfun:

>> V = [2,1,10,4,1,5,12,2,1,4];
>> bsxfun(@(x,y)(x-y).^2, V, V(:))
ans =
     0     1    64     4     1     9   100     0     1     4
     1     0    81     9     0    16   121     1     0     9
    64    81     0    36    81    25     4    64    81    36
     4     9    36     0     9     1    64     4     9     0
     1     0    81     9     0    16   121     1     0     9
     9    16    25     1    16     0    49     9    16     1
   100   121     4    64   121    49     0   100   121    64
     0     1    64     4     1     9   100     0     1     4
     1     0    81     9     0    16   121     1     0     9
     4     9    36     0     9     1    64     4     9     0

This gives the square of the difference of every pair of elements in the vector V.

If you are trying to do something else then please explain what you want to do, and then we can help you to reach your goal.

[mzaya]

Well in my actual data I have a cell array of 30 different cells that each contains a vector. I want to make a loop that will first take the first cell and implement the squared difference with every other cell. So I want to take cell{ 1}-cell{i} where i=1:length(cell). Then the loop should move on to the second cell and take the squared different with every other cell. So cell{ 2}-cell{i} where i=1:length(cell). And so on counting up to 30. I want what is in bold to also be looped so that I don't have to enter this same formula for 30 cells

[Stephen23]

Do the vectors in each cell have the same dimensions and size? Please give the sizes of the cell array and the numeric vectors.

[mzaya]

Yes, my cell array has 1X30 cells and each cell is of equal size of 129X1.

[Stephen23]

It is simpler to process data stored in simple numeric arrays, so the first thing we willl do is to convert that cell array of vectors into one simple numeric array:

 C = num2cell(rand(129,30),1); % fake data
 % convert to numeric array:
 M = cell2mat(C);
 % calculate square of differences of the columns:
 D = bsxfun(@(x,y)(x-y).^2, M, permute(M,[1,3,2]));

You see, no loops are required.