“if” statement using “or” operator.

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Sarah
Sarah el 2 de Feb. de 2012
Comentada: Lewis Waswa el 9 de En. de 2023
Hello everyone,
I have a very simple question....and I have been working on it for some time but cannot figure it out. This is essentially what I would LIKE to say:
for r = 1:length(FreqSec)-1
if FreqSec(1,r+1) > FreqSec(r)*1.01 "OR" FreqSec(1,r+1) <FreqSec(r)*0.99
LagStart = [FreqSec(1,r) r];
break;
end
end
FreqSec is a vector with lots and lots of values....generally within the range of 0.99 and 1.01, except for in a certain interval. I want to detect the exact index point at which the values start changing from the 0.99 to 1.01 range.
Thanks for the help in advance :)
  1 comentario
Aaron Eldridge
Aaron Eldridge el 28 de Abr. de 2016
The "||" counts as an or on matlab

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Walter Roberson
Walter Roberson el 3 de Feb. de 2012
if FreqSec(1,r+1) > FreqSec(r)*1.01 | FreqSec(1,r+1) <FreqSec(r)*0.99
or
if FreqSec(1,r+1) > FreqSec(r)*1.01 || FreqSec(1,r+1) <FreqSec(r)*0.99
The first of these is more general. The second of these, , is the short-circuiting OR that does not bother to evaluate the second expression if it already knows the final result after the first operation. The operator can only be used between expressions that produce scalar outputs.
  3 comentarios
Maximiliano Barbosa
Maximiliano Barbosa el 1 de Dic. de 2022
Thank you
Lewis Waswa
Lewis Waswa el 9 de En. de 2023
A quick question, does this mean that the | evaluattes all the conditions?

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Más respuestas (2)

Geoff
Geoff el 3 de Feb. de 2012
So you want the last index within the valid range?
I don't know why you are multiplying by 1.01 and 0.99. Perhaps you have described the problem incorrectly or that is the cause of your difficulties. What I think you are trying to do is this:
idx = find( FreqSec >= 0.99 & FreqSec <= 1.01, 1, 'last' )
LagStart = [FreqSec(1,idx) idx];
Or, since it's symmetric:
idx = find( abs(FreqSec-1) <= 0.01, 1, 'last' )
If instead you want the index of the first out-of-range value, use:
idx = find( abs(FreqSec-1) > 0.01, 1, 'first' )
The parameter 'first' is optional, but good for clarity.
-g-
  1 comentario
Geoff
Geoff el 3 de Feb. de 2012
Oops, those statements with 'last' are incorrect. You are probably better off doing the 'first' statement and subtracting 1.

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Rehman Tabasum
Rehman Tabasum el 30 de Abr. de 2021
i=5
while i>=-1
pause(1)
fprintf('%d\n',i)
i=i-1
if i==0
break
end
end
this is my code for the start button gui for countdown timer so anyone know how to stop coutdown timer when it is runnnig

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