numbering of matrices generation
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hi if i have
for j=1:3;
B=[A(j,1); A(j,1)]
end;
then how i got the matrices B1 B2 B3 instead of only B .
1 comentario
KSSV
el 23 de Jun. de 2016
How we would know how you got it without telling what is A and what you wanted?
Respuestas (1)
Stephen23
el 23 de Jun. de 2016
Editada: Stephen23
el 23 de Jun. de 2016
>> A = randi(9,3,1)
A =
6
5
9
>> B1 = A([1,1],1)
B1 =
6
6
>> B2 = A([2,2],1)
B2 =
5
5
>> B3 = A([3,3],1)
B3 =
9
9
But almost always creating numbered variables is a really bad idea. Just use indexing instead, because indexing is faster, more reliable, neater, and easier to read and understand than trying to create variable names dynamically. Read these to know why:
Or even better is to learn how to use MATLAB properly and avoid the loop altogether and use indexing:
>> A([1,1],1)
ans =
6
6
>> A([2,2],1)
ans =
5
5
Or if you really want to split A up into smaller matrices:
>> B = num2cell(A(:,[1,1]).',1);
>> B{1}
ans =
6
6
>> B{2}
ans =
5
5
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