For loope small increments

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marvin corado
marvin corado el 11 de Mzo. de 2011
I cannot seem to find the solution to this problem. I write a for loop and i tell it to increment by a small value, but instead of starting at 1, it starts at 2.9110 here is the loop
for m=1:.001:4
m
end
does anyone know what its going on? i expect it to start at 1 and increment by .001 every time so that it goes 1.001, 1.002, 1.003 and so on thank you

Respuesta aceptada

Matt Fig
Matt Fig el 11 de Mzo. de 2011
I don't know why you think this starts at 2.910. Perhaps you are running into the limit of your command window when trying to scroll back up after running the loop. Do this:
for m=1:.001:4
m
pause(.5)
end
Now you should see m incrementing like you expect as it prints slowly out.
  2 comentarios
Paulo Silva
Paulo Silva el 11 de Mzo. de 2011
Matt that code might freak out someone who doesn't know how to stop it (CTRL+C in MSWIN OS)
Matt Fig
Matt Fig el 11 de Mzo. de 2011
True, but I thought everyone know about ctrl+c!

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Más respuestas (4)

Paulo Silva
Paulo Silva el 11 de Mzo. de 2011
It works fine here, try this
m=1:.001:4;
What's the first value of the vector m?

marvin corado
marvin corado el 11 de Mzo. de 2011
yes matt you are right, since the answer was printed in the command window and it always started at 2.910, but when i add the puase it starts at 1 and increments as i expect. thankfully i did know about ctrl_c :)

marvin corado
marvin corado el 11 de Mzo. de 2011
ok but my problem seems to be something else then because my code is supposed to increment M starting at 2 and increment it .0001 up to 3. here is my code
f=0.006;
M= 3;
gamma = 1.4;
L_D=50;
Mx=1;
tol=1e2;
for Mx=2:.0001:3
a =(1-(M^2))/(gamma*M^2);
b = (gamma+1)/(2*gamma);
c = ((gamma+1)*(M^2))/(2+((gamma-1)*M^2));
%friction parameter coefficient for m1
Fp1 = a+(b*log(c));
%guessing
%friction parameter coefficient for guess
a1 =(1-(Mx^2))/(gamma*Mx^2);
b1 = (gamma+1)/(2*gamma);
c1 = ((gamma+1)*(Mx^2))/(2+((gamma-1)*Mx^2));
Fpx = a1+(b1*log(c1));
%Lx = L1star-Lxstar
Fpg=Fp1-Fpx;
%doing table A2 Normal shock
num=1+(((gamma-1)/2)*Mx^2);
den= (gamma*Mx^2)-((gamma-1)/2);
my= sqrt(num/den);
%friction parameter coefficient normal shock
a2 =(1-(my^2))/(gamma*my^2);
b2 = (gamma+1)/(2*gamma);
c2 = ((gamma+1)*(my^2))/(2+((gamma-1)*my^2));
Fpy = a2+(b2*log(c2));
%checking Lx+Ly* = L
X1=Fpg+Fpy;
R=4*f*L_D;
end
if abs(X1-R)<tol
z=Fpy
a=Fpg
a1=a/(4*f)
end
break
but that if statement does not happen for 2:.0001:3 but it happens for 2.5:.0001:3 do you guys know what is going on? thank you
  1 comentario
Matt Fig
Matt Fig el 11 de Mzo. de 2011
Please select a best answer for this question, then start a new one. That way people can search Answers for a specific issue they are having.

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marvin corado
marvin corado el 11 de Mzo. de 2011
should i start a new one? with my question above?
  1 comentario
Matt Fig
Matt Fig el 11 de Mzo. de 2011
Yes, that way we keep one Question per topic.

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