index assignment in matrix.

T(8x2000) matrix, in(8x6500) matrix.

I have the following for applying delays in matrix 'T' into a signal in matrix 'in'(each row of 'in' represents a signal.That is, 'in' has 8 signals, each of 6500 samples):

for d=1:numel(T)
out(d,:)=function(in(n,:),T(d));
end

Everytime 'd' jumps to next column in matrix 'T', then 'n' should reset to 1 and run till 8 along the rows of matrix 'in'. This should continue for all values of 'd' from 1 to 16000.

How can I do it? please help

Answer 1

[Jan]

The question is not clear to me. Perhaps you want:

for d = 1:numel(T)
  out(d, :) = function(in(rem(d, 8) + 1, :), T(d));
end

[EDITED] A typo: "rem(n,8)" -> "rem(d,8)"

[zozo]

I want to know what should come in place of 'n' in the above piece of code.

I want the following:

when d=1,2,3...8

out(1,2,3..8,:)=function(in(1,2,3...8,:),T(1,2,3,...8));

but when d=9,10,11,...16;

out(9,10,11...16,:)=function(in(1,2,3...8,:),T(9,10,11...16));

and

d=17,18,19,...24;

out(17,18,19...24,:)=function(in(1,2,3...8,:),T(17,18,19...24));

.

.

.

.

.

.

and so on till d=15993,15994,15995...16000.

[zozo]

please help.

[Jan]

Dear zozo: I had a typo in the code. I think, you should have been able to fix this by your own.